Question

The function y=-2+5sin(pi/12(x-2)), what is the minimum value?

Answer 1

Answer:

-7

Step-by-step explanation:

We are given that   a function

$y=-2+5 sin(\frac{\pi}{12}(x-2))$

We have to find the minimum value of y.

We know that range of sin x is [-1,1].

$-1\leq sin(\frac{\pi}{12}(x-2))\leq 1$

$-5\leq 5sin(\frac{\pi}{12}(x-2))\leq 5$

$-5-2\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 5-2$

$-7\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 3$

$-7\leq y\leq 3$

Maximum value of y=3

Minimum value of y=-7

Hence, the minimum value of given function =-7

Answer 2

Answer:

-7

Step-by-step explanation:

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