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2 years ago

What are the coordinates of the image of point K(1,3) after a reflection over the line y = -1

Mathematics

2 answers:

N76 [4]2 years ago

8 0

Answer:

(1. -3. is the answer. the first option

Virty [35]2 years ago

7 0

Answer: (-3,3)

Step-by-step explanation:

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Select all the statements that are true.

alexgriva [62]

Answer:

The product of 8x(5x−6) is 40x^2−48x

The product of (x−3)(5x−6) is 5x^2−21x+18

Step-by-step explanation:

<u><em>Verify each option</em></u>

Part 1) The product of 8x(5x−6) is 40x^2−48x

we have

$8x(5x-6)$

Applying distributive property

$8x(5x)-8x(6)\\40x^2-48x$

Compare with the given value

$40x^2-48x=40x^2-48x$

therefore

The statement is true

Part 2) The product of −4x(2x2+1) is −8x^3−5x

we have

$-4x(2x^{2}+1)$

Applying distributive property

$-4x(2x^{2})-4x(1)\\-8x^3-4x$

Compare with the given value

$-8x^3-4x \neq -8x^3-5x$

therefore

The statement is not true

Part 3) The product of (x−3)(5x−6) is 5x^2−21x+18

we have

$(x-3)(5x-6)$

Applying distributive property

$x(5x)-x(6)-3(5x)+3(6)\\5x^2-6x-15x+18\\5x^2-21x+18$

Compare with the given value

$5x^2-21x+18=5x^2-21x+18$

therefore

The statement is true

Part 4) The product of (2x+3)(x^2+3x−5) is 2x^3+9x^2+9x−25

we have

$(2x+3)(x^2+3x-5)$

Applying distributive property

$(2x)(x^2+3x-5)+(3)(x^2+3x-5)\\(2x^3+6x^2-10x)+(3x^2+9x-15)\\2x^3+9x^2-x-15$

Compare with the given value

$2x^3+9x^2-x-15 \neq 2x^3+9x^2+9x-25$

therefore

The statement is not true

8 0

3 years ago

At noon, Sarah headed from Elk City to Isabel at 60 miles per hour. Two hours later, Joan grade from Isabel to Elk City at 46 mi

navik [9.2K]

I thank that 46 + 60= 106 miles per hour
106 - 332= 226 miles per hour
Explain: 106+ 226 = 332 miles per hour

8 0

3 years ago

What are the 2 points ,, red or orange ,, what is the solution

denpristay [2]

Answer:

(-2, 4)

Step-by-step explanation:

y = -3x - 2

y = -x +2

=> -3x - 2 = -x +2

-3x + x = 2 + 2

-2x = 4

x = -2

-x + 2 = y

2 + 2 = y

4 = y

8 0

3 years ago

Can someone solve this?

aleksley [76]

Answer:

Considering the Law of Cosines:

$c^2=a^2+b^2-2ab*cosC$

$a=14mi; b=24mi; c=CA; C=91degrees$

$\cos \left(91^{\circ \:}\right)=-0.01745\dots$

$c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi$

4 0

3 years ago

Half the difference of a number and 16 is negative 2

Reika [66]

Answer:

Step-by-step explanation:

Work backwards. If -2 x 2= -4 then something plus negative four will equal 16, which is 20.

7 0

3 years ago