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Oliga [24]
3 years ago
13

Solve for x: -x^2+5x+6=0

Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

11  and 6

Step-by-step explanation:

hello :

-x²+5x+6=0

-(x+1)(x-6)=0

x+1=0 or x-6=0

x=-1 or x=6

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Simplify (-8q^3r^4s^2)^2
koban [17]

Answer:

64q^6r^8s^4

Step-by-step explanation:

(-8q^3r^4s^2)^2

= (-8)^2 q^(3*2) r^(4*2) s^(2*2)

= 64q^6r^8s^4

3 0
3 years ago
Easiest question in the world no joke this time
Volgvan

Question #25:

One way to solve this is by multiplying the number of packages per serving by the number of guests.

1/4 * 16 = 4 packages to serve 16 guests. This means he doesn't have enough.

A second way to solve this is by diving the number of packages by the number of packages it takes to make on serving.

3 1/2 ÷ 1/4 = 14 guests he can serve. This means he doesn't have enough.

Question #26:

First, find common denominators.

2/3 = 8/12

1/4 = 3/12

Second, subtract.

8/12 - 3/12 = 5/12

Therefore, the tank is 5/12 full at the end of the trip.

Question #27:

1/2 is cut off then 1/3 is cut off. This means 3/6 was cut off to bundle newspapers, then 1/6 was cut off to make parcel. In all, 4/6 was cut off the original string. Afterwards, 2/6 was left over. So, just multiply; 2 * 3 = 6.

Therefore, the original string was as a total of 6 meters.

Best of Luck!

3 0
2 years ago
Which is a factor pair of 72?<br><br>A) 12,6<br><br>B) 14,5<br><br>C)23,4<br><br>D)24,2<br>​
scoundrel [369]

Answer:

the answer is A) 12,6. .

Step-by-step explanation:

.

6 0
2 years ago
A confidence interval was used to estimate the proportion of statistics students that are female. A random sample of 72 statisti
jeyben [28]

Answer:

We need a sample of size at least 13.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence interval: (0.438, 0.642).

The proportion estimate is the halfway point of these two bounds. So

\pi = \frac{0.438 + 0.642}{2} = 0.54

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?

We need a sample of size at least n.

n is found when M = 0.08. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.08 = 1.96\sqrt{\frac{0.54*0.46}{n}}

0.08\sqrt{n} = 1.96\sqrt{0.54*0.46}

\sqrt{n} = \frac{1.96\sqrt{0.54*0.46}}{0.08}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.54*0.46}}{0.08})^{2}

n = 12.21

Rounding up

We need a sample of size at least 13.

3 0
2 years ago
Type the expressions as radicals.<br> Y^5/2
Lapatulllka [165]

Answer:

it will be square root y^5

Step-by-step explanation: Apply the rule x m/n=n√x m to rewrite the exponentiation as a radical.

7 0
2 years ago
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