Write the following equation in the general form Ax+ By+ C:
1 answer:
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Answer:
0.05 seconds; 2.575 m off the ground
Step-by-step explanation:
This is a system of equations that you need to solve for the variables t and h.
h = -5t² + 32t + 2
h = 31.5t + 1
Since h will be the same when the bullet and skeet collide, then h is the same in both equations and can be set equal to each other and then you can solve for t.
-5t² + 32t + 2 = 31.5t + 1
-5t² + 32t + 2 - 31.5t - 1= 31.5t + 1 - 31.5t -1 (move everything to the left side)
-5t² + 0.5t + 1 = 0 (combine like terms)
Now we can use the quadratic formula to solve for the time.
t = (substitute)
t = (multiply)
t = (add)
t = (square root)
t = -0.5/-10 or -9.5/-10 (combine like terms in each situation)
t = 0.05 or .95 (divide)
Since it will only hit it once, the first time it hits is the amount of time, therefore it takes .05 seconds to hit the skeet.
Next, substitute t into one of the equations to find the height at which it occurs.
h = 31.5(0.05) + 1 (substitute)
h = 1.575 + 1 (multiply)
h = 2.575 (add)
Therefore the skeet will be 2.575 meters off the ground.
By using relation between metre and kilometre we got that if The distance from home to the history museum is six and seven-tenths kilometres then he travel 67000 m
What is relation between metre and kilometre?
Relation between metre and kilometre is that 1 kilometre =1000 metre
we know that kilometre and metre are two units of distance and we can convert data from one to another using their relation
Now here given distance is in kilometre
and distance is67 kilometre
We can convert 67 kilometre in metre as
67 kilometre = 67 1000metre
67 kilometre = 67000 metre =67000 m
By using relation between metre and kilometre we got that if The distance from home to the history museum is six and seven-tenths kilometres then he travel 67000 m
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