Please help me Solve P=2x+2w for x thank you

The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial

qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

$\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0$

Solve this equation we get

$p(t)=p_0e^{kt}---(1)$

where p is the present population

p₀ is the initial population

If the initial population as doubled in 5 years

that is time t = 5 years

We get

$2p_o=p_oe^{5k}\\\\e^{5k}=2$

Apply In on both side to get

$Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}$

Substitute $k=\frac{In2}{5}$ in $p(t)=p_oe^{kt}$ to get

$\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}$

Given that population of a community is 9000 at 3 years

substitute t = 3 in ${p(t)=p_oe^{\frac{In2}{5}t }}$

$p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8$

<h3>Therefore, the initial population is 5937.8</h3>

7 0

3 years ago

Let sin t = a, cos t = b, and tan t = c. Write the following expression in terms of a, b, and c.

Ira Lisetskai [31]

We use the trigonometric identities in this problem.

=(sin(t)cos(4π)+sin(4π)cos(t))−(cos(t)cos(8π)−sin(t)sin(8π)) +<span>tan(t)+tan(5π)/1−tan(t)tan(5π)
=</span>sin(t)+0−cos(t)+0+ tan(t)1−0<span>=sin(t)−cos(t)+tan(t)
=</span>a−b+c

8 0

3 years ago

PLZ PLZ PLZ ANSWER THIS!!!!!!!

Sever21 [200]

Answer:

350

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the volume of the cube

miskamm [114]

Answer:

The volume of cube is 125 cm³.

Step-by-step explanation:

Given that the formule of volume of cube is, V = length×width×height. Cube is a 3D form of square, so the sides of the cube are all the same. You have to substitute 5 into the formula,

Let length be 5 cm,

Let width be 5 cm,

Let height be 5 cm,

Volume = 5×5×5

= 125 cm³

7 0

3 years ago

Read 2 more answers

Which ofnthe following shows the correct use of distributive property when solving 1/3(33-x)=135,2

madam [21]

Answer: OPTION C.

Step-by-step explanation:

The missing options are:

$A. (33 - x) = \frac{1}{3} * 135.2\\\\B. (\frac{1}{3} *33) - \frac{1}{3} x = \frac{1}{3} * 135.2\\\\C.(\frac{1}{3} * 33) - \frac{1}{3} x = 135.2\\\\D. (\frac{1}{3} * 33) + \frac{1}{3} x = 135.2$

In order to solve this exercise you need to remember the following:

1. The Distributive property states that:

$a(b+c)=ab+ac\\\\a(b-c)=ab-ac$

2. The multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

In this case the exercise gives you the following equation:

$\frac{1}{3}(33-x)=135.2$

Since you need to solve for the variable "x" in order to find its value, the first step you must apply in the in the procedure is to eliminate the parentheses applying the Distributive property.

Then, you must multiply everyting inside the parentheses by $\frac{1}{3}$ .

Therefore,based on the explanation, you know that the correct use of the Distributive property is:

$\frac{1}{3}*33-\frac{1}{3}x=135.2$

8 0

3 years ago