Answer:
The probability that a randomly selected call time will be less than 30 seconds is 0.7443.
Step-by-step explanation:
We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.
Let X = caller times at a customer service center
The probability distribution (pdf) of the exponential distribution is given by;

Here,
= exponential parameter
Now, the mean of the exponential distribution is given by;
Mean =
So,
⇒
SO, X ~ Exp(
)
To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;
; x > 0
Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)
P(X < 30) =
= 1 - 0.2557
= 0.7443
Answer:
It would be 4:6
Step-by-step explanation:
2*2=4
3*2=6
they both multiply by 2
hopefully that makes sense.
I think c. 10100÷ (12 x 4)
C. 18.88 centimeters. Because with a tilted radius of 5.7. It ranges up. So it would be a higher number SLIGHTLY.
Hope this helps.
Answer:
I Believe that your answer is D. Sorry if i'm wrong.
Step-by-step explanation: