125. To find the answer to these questions, divide the number (50) by the percent in decimal form (40% = 0.4) 50 / 0.4 = 125. To make sure, 125 x 0.4 = 50.
Hey There,
The equation would be y = 4x - 45
Point slope formula
(y-y1)=m(x-x1)
Plug in the numbers
(y-3)=4(x-12)
Solve for y.
4 * x = 4x
4 * -12 = -48
Bring 3 to the other side (change the sign)
-48 +3 = 45
Therefore, the equation would be y = 4x - 45
Answer:

Step-by-step explanation:
Line g passes through (-2,6) and (-3,2).
The slope of line g is given by:

Let's substitute the values to get:

The equation that is perpendicular to line g will have a slope that is the negative reciprocal of 4.
i.e -1/4
If this line passes through (P,Q), then the equation is:

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Explanation:</h2><h2>
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Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.
Remember that for any relation, we have a set
that matches the the domain (also called the set of inputs) of the function and the set
that contains the range (also called the set of outputs).
Suppose our relation is:

So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:

So in this context, the correct option is:
B) (-9,-8, -7, -6, -5}
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)