Answer:
6 and 21 meters long
Step-by-step explanation:
You make an equation from what you got (there are 2 widths and 2 lengths)
2(4w-3)+2w=54---->10w-6=54---> 10w=60 ----> w=6 ---> plug in the rest and you get 21 as the length.
or... make W+L=28 and guess and check!!! takes longer but works!
PEMDAS
do parentheses first
4 x 10=40
40 x 10=400
Answer:
x = 16
Explanations:
The given rquation is:

Step 1: Cross multiply the equations. That is 28 multiplies 4 and 7 multiplies x:

112 = 7x
Step 2: Divide both sides by 7

16 = x x = 16
Answer:
41.64% probability that a butterfly will live between 12.04 and 18.38 days.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the probability that a butterfly will live between 12.04 and 18.38 days.
This is the pvalue of Z when X = 18.38 subtracted by the pvalue of Z when X = 12.04. So
X = 18.38



has a pvalue of 0.4168
X = 12.04



has a pvalue of 0.0004
0.4168 - 0.0004 = 0.4164
41.64% probability that a butterfly will live between 12.04 and 18.38 days.
(x²+4)(x²+4) =x^4+8x²+16
B. x4 + 8x2 + 16