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xz_007 [3.2K]
3 years ago
8

How do you do this?please help if possible!

Mathematics
2 answers:
stellarik [79]3 years ago
7 0
(a) need to find the number of books, we'll call it "b". then the money (6w) minus the cost of books (17b) equals change left over (w)
6w - 17b = w
6w - w = 17b
5w = 17b
(5/17)w = b

(b) if w = 34
(5/17) *34 = b
10 = b
Luden [163]3 years ago
3 0
A) Solution:
Angela bought some books for $17 each.
That means , she bought x books for $17x
Initially, she had $6w.Later she has $w left.

Writing this as a equation,
6w-17x=w
6w-w=17x
5w=17x
x=5w/17➡Ans 1

b) Solution:
If w=34,
↪x=5×34/17
=10➡Ans 2
So , she bought 10 books in this case.

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Match the numerical model to the corresponding graphical and algebraic models.
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Answer:

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The law of detachment can be used to draw a conclusion from the following statements: "It will be sunny on Tuesday." "I will alw
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8 0
3 years ago
Which property of equality is used in solving x + 8 = 9?
stiv31 [10]

Answer:

Subtraction Property of Equality.

Step-by-step explanation:

To solve x + 8 = 9, you need to subtract 8 from both sides of the equation. So, you would be using the Subtraction Property of Equality.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
ew if you're attracted to those mexican boys with the dirty permed hair and who sags their pants and smell musty too then stay a
nlexa [21]

Answer:

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