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3 years ago

PLEASE HELP !!!!

Mathematics

1 answer:

Mumz [18]3 years ago

7 0

Answer:

9 hr

Step-by-step explanation:

vary directly means you should think about a constant being multiply to one variable to get another variable.

So we have E=kH

where E=earnings and H=hours and k is the constant of proportionality

So they give us when H=7 we have E=77 giving us 77=k(7) which means the constant of proportionality is 11

So that means no matter what the E and H are k is 11

So we have the equation is E=11H

Replace E with 99 and solve for H

99=11(H)

So H=9

9 hours

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Use the ratio table to find the unit rate with specified units.

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It’s 10.5 I’m pretty sure

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6. In the figure below, measure of angle 1 = 3x + 5, measure of angle 2 = 5x - 18, and measure of angle 3 = 7x-2

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See photo for solution and mark me as brainliest if i helped :)

A: although it seems like they are forming a 90º angle, they actually add up to a 89 º angle and therefore are not complementary

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3 years ago

250 grams of sugar cost 150 dollars at Shop X. 100 grams of sugar cost 95 dollars at Shop Y. What is the difference in cost per

nata0808 [166]

<h2>Answer:</h2>

350 dollars

<h2>Step-by-step explanation:</h2>

<em>(step 1) Find the cost per kilogramme of sugar in shop X</em>

In shop X:

250 grams of sugar costs 150 dollars.

<em>Remember that;</em>

1000 grams = 1 kilogramme.

=> 250 grams will be equal to 0.25 kilogramme

Therefore (replacing 250 grams with 0.25 kilogramme) in shop X;

0.25 kilogramme of sugar costs 150 dollars

Now, if

0.25 kilogramme = 150 dollars,

=> 1 kilogramme = 150 dollars x 1 kilogramme / 0.25 kilogramme

=> 1 kilogramme = 600 dollars

Therefore, the cost per kilogramme of sugar in shop X is 600 dollars

<em>(step 2) Find the cost per kilogramme of sugar in shop Y</em>

In shop Y:

100 grams of sugar costs 95 dollars.

<em>Remember that;</em>

1000 grams = 1 kilogramme.

=> 100 grams will be equal to 0.1 kilogramme

Therefore (replacing 100 grams with 0.1 kilogramme) in shop Y;

0.1 kilogramme of sugar costs 95 dollars

Now, if

0.1 kilogramme = 95 dollars,

=> 1 kilogramme = 95 dollars x 1 kilogramme / 0.1 kilogramme

=> 1 kilogramme = 950 dollars

Therefore, the cost per kilogramme of sugar in shop Y is 950 dollars

<em>(step 3) Find the difference in cost per kilogramme of sugar between the two shops</em>

The difference is calculated by subtracting the cost per kilogramme of sugar in shop X from the cost per kilogramme of sugar in shop Y. i.e

=> cost per kilogramme of sugar in shop Y - cost per kilogramme of sugar in shop X

=> 950 dollars - 600 dollars

=> 350 dollars.

Therefore, the difference in cost per kilogramme is 350 dollars

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3 years ago

Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.

dsp73

Answer:

The required sequence is $a_n=20(\frac{1}{2})^{n-1}$ . The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, $a_2=10,a_3=5,a_4=2.5,a_5=1.25$

$r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}$

The common ratio of GP is 1/2.

$r=\frac{a_2}{a_1}$

$\frac{1}{2}=\frac{10}{a_1}$

$a_1=20$

The first term of the sequence is 20.

The formula for sequence is

$a_n=a(r)^{n-1}$

Where a is first term and r is common difference.

The required sequence is

$a_n=20(\frac{1}{2})^{n-1}$

The formula for rate of change is

$m=\frac{f(x_2)-f(x_1)}{x_2-x_1}$

The average rate of change from n = 1 to n = 3 is

$m=\frac{f(3)-f(1)}{3-1}$

$m=\frac{5-20}{3-1}$

$m=\frac{-15}{2}=-7.5$

Therefore the required sequence is $a_n=20(\frac{1}{2})^{n-1}$ . The average rate of change from n = 1 to n = 3 is -7.5.

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3 years ago

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Give an example of a polynomial that has the asymptotes of x=5 and y=0.5

BaLLatris [955]

(x²+4x+3)/2(x²-10x+25)

the horizontal asymptote when the numerator and the denominator have the same degree (in this case, both of a degree of 2) is ration of the coefficients of the numerator and denominator. In this case, the coefficient for numerator x² is 1, and the coefficient for the denominator 2x² is 2, so the horizontal asymptote is y=1/2=0.5

the vertical asymptote is the x value. the denominator cannot be zero, if x²-10x+25=0, x would be 5, so the vertical asymptote is x=5

this is just one example. There can be others:
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