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3 years ago

Find f(4) if f(x) = x —6

Mathematics

2 answers:

Andru [333]3 years ago

5 0

Answer:

-12

Step-by-step explanation:

frutty [35]3 years ago

4 0

Use the substitution method

f(4)=4-6

=-2

Answer :-2

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Write the recursive formula for 16,23,30,37

4vir4ik [10]

Answer:

Arithmetic Sequence

Step-by-step explanation:

Arithmetic Sequence

4 0

2 years ago

Write an equation of the line that passes through the points (0,4)(0,4) and (2,10)(2,10). $y=

lutik1710 [3]

I am going to guess you want to find a line which passes through the points (0,4) and (2,10)...

y₂-y₁ / x₂-x₁
10 - 4 / 2 - 0
6 / 2
3....slope
(0,4) .....b

y = 3x + 4

3 0

3 years ago

Need help with this, simple but I don't understand/remember how to do it.

Lorico [155]

By using definition of proportionality and Pythagorean theorem, the values of x and y associated with the geometrical system formed by two right triangles are 36 / 5 and 104 / 5, respectively.

<h3>How to analyze a geometrical system formed by two proportional right triangles</h3>

Herein we find a picture of a geometrical system formed by two proportional right triangles with two variables: {x, y} These variables can be found by using the definition of proportionality and the Pythagorean theorem:

5 / 8 = 12 / (12 + x) = 13 / y

Then, we proceed to solve the system formed by two equations:

(12 + x) / 12 = 8 / 5

12 + x = 96 / 5

x = 96 / 5 - 12

x = 36 / 5

y / 13 = 8 / 5

y = 104 / 5

To learn more on right triangles: brainly.com/question/6322314

#SPJ1

7 0

1 year ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

2 years ago

Read 2 more answers

What is the equation of this function after it is reflected over the x-axis?

erma4kov [3.2K]

Answer: F(x)=-(x+4)^3

That's it

5 0

3 years ago

Find f(4) if f(x) = x —6​

Find f(4) if f(x) = x —6