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olga55 [171]
3 years ago
13

In a zoo theres 5 tigers, 4 lions, and 7 cheetahs. What is the ratio of Cheetah: Tiger?

Mathematics
1 answer:
Over [174]3 years ago
8 0

Answer:

7:5

Step-by-step explanation:

there are 7 cheetahs and 5 tigers soooooo

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Lesson 13.3 Checkpoint
Arte-miy333 [17]

Answer:

a. LK = 4√3, JL= 4√6

b.  PQ = 10√3, RP = 5√3

Step-by-step explanation:

a. LK =4√3,

LK=KJ= 4√3

sin(45°) = opposite/hypotenuse

hypotenuse (JL)= opposite/sin 45° = 4√3/√2/2 = 8√3/√2 = 8√3√2/2 = 4√6

b.

cos 30° = adjacent/hypotenuse = QR/PQ = 15/PQ

cos 30° = 15/PQ

PQ = 15/cos 30° = 15/√3/2)= 30/√3 = 30√3/3 = 10√3

tan 30° = opposite/adjacent = RP/QR

√3/3 = RP/QR

√3/3 = RP/15

RP = √3*15/3 = 5√3

3 0
3 years ago
Which equation has no solution?
sladkih [1.3K]

Answer:

-2(6-3x)=-12+6x

Step-by-step explanation:

If you do the distributive property first and look at the other side of the = sign they are the same, which means that the answer would be x=x, which isn't a solution.

8 0
3 years ago
The rule for this number sequence is (n+3) x 2
zzz [600]
6 + 12 = 18
18 + 24 = 42
Double the difference between every 2 numbers (12 x 2 = 24 x 2 = 8)
42 + 48 = 90
90 is the missing number
Happy to Help!
8 0
3 years ago
If on a scale drawing 24 inches equals 10 ft. what does 1/8 inches equal
OLga [1]

Answer:

 \large\boxed{\large\boxed{(5/96)ft\approx 0.052ft}}

Explanation:

1. Use the scale ratio to set a proportion with the unknown lenght.

       24inches/10ft=(1/8)inches/x

2. To solve for x, use cross multiplication:

        24inches\times x=10ft\times(1/8)inches

3. Divide both sides by 24inches:

          x=10ft\times(1/8)inches\times (1/24inches)

4. Simplify:

          x=10ft/192=(5/96)ft\approx 0.052ft

6 0
3 years ago
A circle with a circumference of 51 inches to find the area
Kaylis [27]

\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=51 \end{cases}\implies 51=2\pi r\implies \boxed{\cfrac{51}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \implies A=\pi \left( \cfrac{51}{2\pi } \right)^2\implies A=\cfrac{51^2}{2^2\pi }\implies A\approx 206.98

4 0
2 years ago
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