To evaluate the equation <span> log7 343 (with base 7) , we pattern this to its standard form log a b (with base a). this expression is equal to log b over log a. In this case, the expression given is equal to log 343 / log 7. The answer to this problem is 3. 3^7 is equal to 343.</span>
You question is of two parts.
For the first part:
<span>A group of men and women were asked what their favorite pet was, and the results of the survey were tabulated.
![\begin{center} \begin{tabular} {|c|c|c|c|c|} & Cats & Dogs & Other & Total \\ [1ex] Male & 42 & 58 & 6 & 106 \\ Female & 52 & 48 & 2 & 102 \\ [1ex] Total & 94 & 106 & 8 & 208 \end{tabular} \end{center}](https://tex.z-dn.net/?f=%5Cbegin%7Bcenter%7D%0A%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0A%20%26%20Cats%20%26%20Dogs%20%26%20Other%20%26%20Total%20%5C%5C%20%5B1ex%5D%0AMale%20%26%2042%20%26%2058%20%26%206%20%26%20106%20%5C%5C%0AFemale%20%26%2052%20%26%2048%20%26%202%20%26%20102%20%5C%5C%20%5B1ex%5D%0ATotal%20%26%2094%20%26%20106%20%26%208%20%26%20208%0A%5Cend%7Btabular%7D%0A%5Cend%7Bcenter%7D)
</span>Let event A be defined as randomly
choosing someone who picked cats or dogs as their favorite pet. Let
event B be defined as a randomly
chosen person being male.
Find P(B| NOT A).
P(A) = P(choosing cat) + P(choosing dog) =

P(NOT A) =

P(B and NOT A) = P(males that did not choose cat or dog) =

P(B | NOT A) =

For the second part of the question.
<span>Petey
is considering investing $19 in a certain company. Financial advisors
forecast that there is a 30% chance that the stock will increase in
value by 10%, and a 70% chance he will lose his initial investment.
Determine if Petey should make the investment, and find the expected
value of the investment.
If his investment increases by 10%, the value of the investment will be 1.1 x $19 = $20.90 with a probability of 30% or 0.3
The expected value of the investment is given by

Therefore, Petey should not make the investment as there is an expectation of a loss from the investment.
</span>
Answer:
Formula
A = 1/2 b * h
Substitute
Area = 60 in^2
b = x
h = 2x - 1
60= 1/2 * x * (2x - 1)
Solve
60 = 1/2 * x (2x - 1) Multiply by 2
60 * 2 = x(2x - 1)
120 = x (2x - 1) Remove the brackets.
120 = 2x^2 - x Subtract 120 from both sides.
2x^2 - x - 120 = 0 This factors.
(2x + 15)(x - 8) = 0
Solve for x
2x + 15 = 0
2x = - 15
x = -15/2
x = - 7.5 a negative measurement is useless. Discard this answer.
x - 8 = 0
x = 8
Area (Check)
base = 8
height = 16 - 1 = 15
Area = 1/2 * 8 * 15 = 60 as it should
Answer
Use Area = 1/2 * b * h to find the base and the height.Step-by-step explanation:
Do the crossing out method. so if it is 2.50 per pound for peaches, try A, 11 pounds. 2.50 times 11 is 27.5, and now we have the rest, 154 pounds as apples so we multiply it by 1.75 which is 269.5, we add them up and we dont get 337.50, so we try out b, 18 times 2.5 is 45 so we still have 147 pounds left for apples, multiply it by 1.75 which is 257.25 and if we add up 45 and 257.25 we dont get 337.5 so now we try c which is 65, multiply it by 2.5 its 162.5 and we have 100 pounds of apples left. we do the same and we get 175, 175 plus 162.5 is 337.5 so C/3 is the correct answer
Answer:
18.46
Step-by-step explanation:
find the area using SSS, then solve for height