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nexus9112 [7]
3 years ago
5

Which statements represent the relationship between y=2^x and y=log2 x?

Mathematics
1 answer:
laila [671]3 years ago
3 0
Y = 2^x and y = log₂x

Exponents and logs (to the same base = 2) are inverses of each other.
All inverse functions are symmetric about line y = x

y = log₂x is NOT the logarithmic form of y = 2^x
The logarithmic form of y = 2^x is x = log₂y (NOT y = log₂x)

Answer: A, C
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The Moores family paid $6 more for skate rentals than the Cotters did. Together the two families paid $30 for skate rentals. How
Mademuasel [1]
<span>Moores Family Paid = 6 dollars mores for skate rental than the cotters did.
30 dollars = the total amount they paid for skate rentals.
Let Family Moore have the variable X
Let the Family Cotters have the variable Y
=> x = y + 6
=> y = 30 – 6 / 2
First, let’s solve the Y
=> Y – 30 – 6 / 2
=> Y = 24 / 2
=> y = 12
Now, let’s solve for X
=> X = y + 6
=> x = 12 + 6
=> X = 18

</span>



8 0
2 years ago
Graph the system of equations.<br> 2x - y=4<br> 1 x - y = -2
dybincka [34]

PPLMway will help

Step-by-step explanation:

4 0
3 years ago
Which proportion can be used to find 65% of 90?
tia_tia [17]

Answer:

58.5

Step-by-step explanation:

0.65 decimal form

then times that by 90

then you got the answer 58.5

7 0
2 years ago
If the door to the library is at (2, 4), the door to the mall is at (8, 2), and one
guapka [62]

Answer:

6 miles

Step-by-step explanation:

The distance formula is expressed as;

D = √(x2-x1)²+(y2-y1)²

D = √(2-4)²+(8-2)²

D = √(-2)²+(6)²

D = √4 + 36

AD = √40

AD = 6.32

Hence the approximate distance between the library  and the mall is 6 miles

5 0
3 years ago
To obtain the area of a sector, what fraction is multiplied by the area of a circle (A = πr2)?
romanna [79]
Let r be a radius of a given circle and α be an angle, that corresponds to a sector.

The circle area is A=\pi r^2 and denote the sector area as A_1. 
Then  \dfrac{A_1}{A}= \dfrac{\alpha}{2\pi}  (the ratio between area is the same as the ratio between coresponding angles).

A_1=\dfrac{\alpha}{2\pi} \cdot A=\dfrac{\alpha}{2\pi} \cdot \pi r^2= \dfrac{r^2\alpha}{2}.

6 0
3 years ago
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