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3 years ago

12pts :3 please try to answer fast thanks

Mathematics

2 answers:

Xelga [282]3 years ago

5 0

The answer is 6 . (3x4)/(4x3)-10 . 3x4=12 . 4x3= 12 . 12-10=2 12/2=6

vodomira [7]3 years ago

4 0

Answer,

Explanation,

All they want you to do is input the numbers given into the eqation.

Let's rewrite the eqation,

3 x 4/ 4 x 3 - 10

Now evaluate,

3 x 4 = 12

4 x 3 = 12

12 - 10 = 2

12/2 = 6

Hope this helps :-)

3 x 4/ 4 x 3 - 10

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Step-by-step explanation:

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2 years ago

It is not a function because both (2, 2) and (2,−2) have the same x-coordinate. It is a function because both (2, 2) and (2,−2)

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Answer:

It is not a function because both (2,2) and (2,-2) have the same x-coordinate.

Step-by-step explanation:

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So, in (2, 2) and (2,-2)

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3 years ago

HELP!!! Lucas deposits $250,000 into two investment accounts. Over a year, the first account

prohojiy [21]

The amount deposited in the account that earns 3.6% interest is $57,600 and the amount deposited in the account that earns 2.1% interest is $192,400

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$256,114 - $250,000 = $6,114

The second step is to formulate two set of equations and use simultaneous equation to solve the question

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0.036a + 0.021b = $6,114 equation 2

Where a represent amount deposited in the account that earns 3.6% interest

b represent amount deposited in the account that earns 2,1% interest

Multiply equation 1 by 0.036

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divide both sides of the equation by 0.015

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Substitute for b in equation 1

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2 years ago

Of 575 broiler chickens purchased from various kinds of food stores in different regions of a country and tested for types of ba

chubhunter [2.5K]

Answer:

a) $0.68 - 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.630$

$0.68 + 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.730$

And the 99% confidence interval would be given (0.630;0.730).

b) We are 99% confident that the true proportion of infected chickens are between 0.63 (63%) and 0.73 (73%)

c) For this case the answer would be No. Since all the required assumptions in order to construct the confidence interval are satisfied, so then the results can be assumed for all the population

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\hat p =0.68$ represent the estimated proportion

n=575 is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.68 - 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.630$

$0.68 + 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.730$

And the 99% confidence interval would be given (0.630;0.730).

Part b

We are 99% confident that the true proportion of infected chickens are between 0.63 (63%) and 0.73 (73%)

Part c

For this case the answer would be No. Since all the required assumptions in order to construct the confidence interval are satisfied, so then the results can be assumed for all the population

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3 years ago