Answer:
3 with a remainder of 4 beads
Step-by-step explanation:
if you want to put 10 beads on each bracelet but you only have 34 beads you are going to do subtraction (this is division but subtraction is the easiest way to explain it) so you have 34 bead and that’s more than 10 so you can make a bracelet so subtract 10 from 34, so now you have 24 beads and one bracelet, now 24 is greater than 10 so subtract again, 24-10 which is 14 so now you have 14 beads and 2 bracelets and 14 is greater than 10 so we can make another, 14-10 is 4 so now you have 4 beads and 3 bracelets now 4 is less than 10 so you can’t make another (hope this helps)
The drawing shows a circle, with the two lines forming a cross assumed to be perpendicular to each other, so this is most likely to be a square, as the four points at which the perpendicular lines intersect with the circle can be connected to form a square.
We would need 3 points for an equilateral triangle, 5 for a pentagon, and 6 for a hexagon, which do not fit the current steps.
Soo first apply the exponent rule (2^5)^1/3*1/4
1/3*1/4= 1/12
so (2^5)^1/12
then you apply the exponent rule again 2^5*1/2
so 5*1/12= 5/12
So the answer would be 2^5/12
Step-by-step explanation:
Since line NL is not necessarily congruent to MQ (labelled with different congruent marks), triangle NLM is not congruent to triangle MQP.
Instead, triangles NLM and QPM are congruent.
Answer:
9 represents the initial height from which the ball was dropped
Step-by-step explanation:
Bouncing of a ball can be expressed by a Geometric Progression. The function for the given scenario is:
The general formula for the geometric progression modelling this scenario is:
Here,
represents the initial height i.e. the height from which the object was dropped.
r represents the percentage the object covers with respect to the previous bounce.
Comparing the given scenario with general equation, we can write:
= 9
r = 0.7 = 70%
i.e. the ball was dropped from the height of 9 feet initially and it bounces back to 70% of its previous height every time.
