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3 years ago

16 From her part-time job, Monika can earn a regular

Mathematics

1 answer:

son4ous [18]3 years ago

8 0

First do 3/8 of 120
Then

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What is the solution to this equation?<br> 6x + 10 - 2x= 7 + 23

Strike441 [17]

Answer:

$\boxed{x=5}$

Step-by-step explanation:

First, you need to combine like terms in order to begin simplifying. This is done by subtracting 2x from 6x. Also, add 7 to 23.

6x + 10 - 2x = 7 + 23

4x + 10 = 7 + 23

4x + 10 = 30

Now, you have a two-step equation. Subtract 10 from both sides, and then divide by 4.

4x + 10 = 30

4x = 20

x = 5 is the final answer.

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3 years ago

What is the equation of a circle with center (-7,4) and radius 8?

enot [183]

The answer to this question is
B. (x+7)²+(y-4)²=64

I hope this helps!!!!!!!

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3 years ago

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Is -27 divided by (-3) positive or negative & how

zloy xaker [14]

Answer:

Step-by-step explanation:

-27/-3

27/3 is 9

each of them have a negative so it stays positive

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3 years ago

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Which notation best represents the phrase “no more than 200”?a. 200 d.≥ 200 plz hurry i need asnwer asp

ElenaW [278]

Answer:

D it is d my guy you have fun with that

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3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

Yuri [45]

Let the curve C be the intersection of the cylinder

$16x^2+y^2=16$

and the plane

$x+y+z=1$

The projection of C on to the x-y plane is the ellipse

$16x^2+y^2=16$

To see clearly that this is an ellipse, le us divide through by 16, to get

$\frac{x^2}{1}+ \frac{y^2}{16}=1$

$\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1$ ,

We can write the following parametric equations,

$x=cos(t), y=4sin(t)$

for

$0\le t \le 2\pi$

Since C lies on the plane,

$x+y+z=1$

it must satisfy its equation.

Let us make z the subject first,

$z=1-x-y$

This implies that,

$z=1-sin(t)-4cos(t)$

We can now write the vector equation of C, to obtain,

$r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))$

The length of the curve of the intersection of the cylinder and the plane is now given by,

$\int\limits^{2\pi}_0 {|r'(t)|} \, dt$

But

$r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))$

$|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}$

$\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184$

Therefore the length of the curve of the intersection intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0

3 years ago