Create a sequence in which 1 1/4 is added to each number

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. Following are the amounts measured in a

dlinn [17]

Answer:

The mean volume is 12 ounces.

Step-by-step explanation:

In this case we need to test whether the mean volume the machine fills the beverage cans with is 12 ounces or not.

The hypothesis for this test can be defined as:

H₀: The mean volume is 12 ounces. i.e. μ = 12 ounces.

Hₐ: The mean volume is not 12 ounces. i.e. μ ≠ 12 ounces.

As the population standard deviation is not known, we will use a t-test for single mean.

The sample mean and sample standard deviation is:

$\bar x=\frac{1}{n}\sum X\\=\frac{1}{8}\times [11.98+12.08+11.87+11.95+11.89+12.01+11.97+12.10]\\=11.98$

$\text{s} = \sqrt{\dfrac{\sum_{i=1}^{n}(x_i - \overline{x})^{2}}{n - 1}}\\=\sqrt{\dfrac{\sum_{i=1}^{n}(11.98 - 11.98)^{2}}{8 - 1}}+\sqrt{\dfrac{\sum_{i=1}^{n}(12.08- 11.98)^{2}}{8 - 1}}+...+\sqrt{\dfrac{\sum_{i=1}^{n}(12.10- 11.98)^{2}}{8 - 1}}\\=0.0815$ Compute the test statistic as follows:

$t=\frac{\bar x-\mu}{\s/\sqrt{n}}=\frac{11.98-12}{0.0815/\sqrt{8}}=-0.69$

The test statistic value is -0.69.

Decision rule:

If the p-value of the test is less than the significance level, then the null hypothesis will be rejected.

Compute the p-value of the test as follows:

$p-value=2P(t_{7}$

*Use a t-table.

The significance level of the test is, α = 0.05.

p-value = 0.512 > α = 0.05

The null hypothesis was failed to be rejected.

Hence, it can be concluded that the mean volume is 12 ounces.

5 0

3 years ago

In ADEF, f = 610 inches, e = 590 inches and ZE=70°. Find all possible values of ZF,

Elina [12.6K]

Answer:

"76°" is the appropriate solution.

Step-by-step explanation:

Please find attachment of the diagram according to the given query.

The given values are:

In ΔDEF,

f = 610 inches

e = 590

∠E = 70°

∠F = ?

By using the law of sines, we get

⇒ $\frac{Sin E}{e} =\frac{Sin F}{f}$

On substituting the values, we get

⇒ $\frac{Sin70^{\circ}}{590} =\frac{SinF}{610}$

On applying cross multiplication, we get

⇒ $SinF=\frac{610\times Sin 70^{\circ}}{590}$

On substituting the values, we get

⇒ $=\frac{61\times 0.95969262}{59}$

⇒ $=\frac{57.3212499}{59}$

⇒ $=0.971546608$

now,

⇒ $F=Sin^{-1}(0.971546608)$

⇒ $=76^{\circ}$

4 0

3 years ago

To form the image, the pre image moved

Vladimir [108]

The answer is b. two units right and three up

5 0

3 years ago

A large company is expanding its workforce and needs to hire some new administrative assistants. They found the relationship bet

Inessa [10]

The graph on #6 describes a scatterplot. Because years of experience is the input, this makes the starting salary our output. Finding the best fitting line in a scatterplot requires the line to follow a trajectory similar to that of the points. As a result, there will be outliers. Since I don't know what "the calculator" is meant by this problem, I have used a different program. I hope it works for you. Good luck.

4 0

3 years ago

Select all of the equations that have graphs with the same y-intercept (starting amount).

attashe74 [19]

Answer: y=3x-8, y=5x-8, and y=2x-8

Step-by-step explanation:

These equations are all lines in slope-intercept form (y=mx+b where b is the y-intercept). y=3x-8, y=5x-8, and y=2x-8 all have -8 as the b value. Therefore, these equations have the same y-intercept.

8 0

3 years ago