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Levart [38]
3 years ago
10

Wht is 1,500,000 divided by 20,000

Mathematics
2 answers:
Semmy [17]3 years ago
4 0
The answer to your problem would be 75. 
hope it helps :)
Oxana [17]3 years ago
3 0
I think the answer is 75
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For which of the following counts would a binomial probability model be reasonable? a. The number of traffic tickets written by
timama [110]

Answer:

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 assuming numbers (0,1,2,3,4,5,6,7,8,9) so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n, p)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

The conditions to apply this distribution is that we have the parameters fixed n and p.

Let's analyze one by one the possible solutions:

a. The number of traffic tickets written by each police officer in a large city during one month.

False, the number of traffic tickets written by each police is not a fixed amount always, so then the value of n change and we can't apply a binomial model for this case.

b. The number of hearts in a hand of five cards dealt from a standard deck of 52 cards that has been thoroughly shuffled.

False, not all the hands of size 5 are equal and since we can't ensure this condition then the binomial model not apply for this case

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

d. The number of phone calls received in a one-hour period.

False, the number of phone calls change by the hour and is not always fixed so then we don't have a valu for n, and the binomial model not applies for this case.

e. All of the above.

False option C is correct.

5 0
3 years ago
A length of rope is stretched between the top edge of a building and a stake in the ground. The rope also touches a tree halfway
alexgriva [62]
The answer is 18 ft because 36 divided by 2 is 18
4 0
3 years ago
Which equation listed below, when solved, shows how to find the radius of a circle if the diameter is 4 inches?
Arturiano [62]
If the Diameter Is 4 inches then the radius will be 2 inches!

Hope I Helped!
6 0
3 years ago
Read 2 more answers
A bag contains blue and yellow marbles. Two marbles are drawn without replacement. The probability of selecting a blue marble an
exis [7]
 blue marbles
y = yellow marbles
 Sum = b+y
 The <span>chance of a blue marble being drawn first is:
b / (b+y) = 0.55 
</span>The <span>chance of a blue marble being drawn first then a yellow next is:
</span>b / (b+y) * y / (b+y-1) = 0.37
This can be solve easily by using a theorem of Bayes 
0.37/0.55 = .67 or 67%
7 0
3 years ago
Three lines of crops in a garden form a triangular shape. Strawberries are planted in a 10 ft line and green beans are planted i
Marat540 [252]

Answer:

p = 19.18

Step-by-step explanation:

This question is illustrated using the attachment and will be solved using cosine formula

a^2 = b^2 + c^2 - 2bcCosA

<em>Let the strawberry side be s, the Green beans be b and the pumpkins be p.</em>

<em />

The cosine formula in this case is:

g^2 = s^2 + p^2 - 2spCosG

Where

s = 10

g = 18

The equation becomes

18^2 = 10^2 + p^2 - 2 * 10 * p * Cos\ 68

324 = 100 + p^2 - 20 * p * 0.375

324 = 100 + p^2 - 7.5p

Collect Like Terms

p^2 - 7.5p + 100 - 324 = 0

p^2 - 7.5p - 224 = 0

Using quadratic formula:

p = \frac{-b\±\sqrt{b^2-4ac}}{2a}

Where

a = 1

b = -7.5

c = -224

p = \frac{-(-7.5)\±\sqrt{(-7.5)^2-4*1*-224}}{2*1}

p = \frac{7.5\±\sqrt{56.25+896}}{2}

p = \frac{7.5\±\sqrt{952.25}}{2}

p = \frac{7.5\± 30.86}{2}

p = \frac{7.5 + 30.86}{2} or p = \frac{7.5 - 30.86}{2}

p = \frac{38.36}{2} or p = \frac{-23.36}{2}

p = 19.18 or p = -11.68

But length can not be negative.

So:

p = 19.18

6 0
2 years ago
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