Hello
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =2 y' = - 1
calculate a :
let : y = ax+b .....(D)
....<span>3y-x=7</span>....(D') or y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line : y-y' =a(x-x')
y+1 =(-3) (x-2)
When you write a function in the form
, y is the dependent variable, and x is the independent variable.
So, if b is the independent variable, it means that we have to solve the expression for r.
To do so, we perform the following steps: start with

Add 12 to both sides

Divide both sides by 4:

So, we wrote the expression in the form
, which means that r is the dependent variable and b is the independent variable, as requested.
I would think that it would be A.... I am an expert but, only in 8th, so I would double check.
Answer:
2
Step-by-step explanation:
The equation for a line is:
y=mx+b
Where m is the slope, b is the y-intercept, and x and y are the x and y coordinates.
The equation given to us is:
y=2x+3
Therefore 2 is the slope
Answer:
3x+8=0
x=-8/3The face of the denominator must be 0
And the face and denominator of the fraction must be positive
Step-by-step explanation: