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Sergio [31]
3 years ago
7

Please some one help me.​

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0

Answer:

-11

Step-by-step explanation:

You need to take the absolute value of 12-15 which would be 3. Then take -8-3 which would be -11

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A dealer sold 200 tennis racquets. Some were sold for $33 each, and the rest were sold on sale for $18. The total receipts form
Mumz [18]

120 tennis racquets were sold for $ 18 each

<em><u>Solution:</u></em>

Let x = number that sell for $18 each

Then, 200 - x = number that sell for $33 each

<em><u>The total receipts form these sales were 4800 dollars</u></em>

Thus we frame a equation as:

number that sell for $18 each x 18 + number that sell for $33 each x 33 = 4800

x \times 18 + (200-x) \times 33 = 4800\\\\Solve\ the\ above\ equation\ for\ x\\\\18x + 6600 - 33x = 4800\\\\Move\ the\ variables\ to\ one\ side\\\\18x-33x = 4800-6600\\\\-15x = -1800\\\\Divide\ both\ sides\ of\ equation\ by\ -15\\\\x = 120

Thus 120 tennis racquets were sold for $ 18 each

6 0
3 years ago
At the bank, Mr Smith changes a £5 note for 20p pieces.<br> How many 20p pieces does he-get?
Sindrei [870]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
HELP ME HOW DO I DO THIS ITS REALLY HARD
storchak [24]

Answer:

I can’t just tell you the answer cause that’s all your looking for let me know what u need help with

Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
2 years ago
20 POINTS
zysi [14]

Answer:

I think they are all letter A

Step-by-step explanation:

6 0
2 years ago
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