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4 years ago

How many moles of NaCl are in 25.0 mL of 3.2 M solution?

Chemistry

2 answers:

Fynjy0 [20]4 years ago

8 0

0.08 moles is the answer

gizmo_the_mogwai [7]4 years ago

4 0

0.08 moles

This is because you times 3.2M by 25 ml in litres which is 0.025

3.2 x 0.025 = 0.08

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Provide the name(s) for the tertiary alcohol(s) with the chemical formula C6H14O that have a 4-carbon chain. Although stereochem

pochemuha

Answer:

Explanation:

A tertiary alcohol is a compound (an alcohol) in which the carbon atom that has the hydroxyl group (-OH) is also bonded (saturated) to three different carbon atoms.

Based on the question, the only tertiary alcohol that can result from C₆H₁₄O that have a 4-carbon chain is

2-hydroxy-2,3-dimethylbutane

H OH H H

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H - C - C - C - C - H

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H CH₃ CH₃ H

From the above, we can see that the carbon atom having the hydroxyl group is also bonded to three other carbon atoms. And since we aren't considering stereochemistry, this is the only tertiary alcohol we can have with a 4-carbon chain

4 0

3 years ago

how many moles of sodium hydroxide (NaOH) are required to completely neutralize 2 mol of nitric acid (HNO3)

Brut [27]

2 moles of sodium hydroxide will be needed.

<h3>Explanation:</h3>

Sodium hydroxide is a compound which is a base and nitric acid is the acid. The formula of the nitric acid is HNO3 and that of sodium hydroxide is NaOH.

The reaction between them are

NaOH +HNO3 =NaNO3 +H2O.

So here we can see that 1 mole of sodium hydroxide reacts with 1 mole of nitric acid to produce 1 mole of sodium nitrate and 1 mole of water.

So for 2 moles of nitric acid, 2 moles of sodium hydroxide will be required.

6 0

3 years ago

In the reaction N2O4(g) 2NO2(g), what changes in color would you expect as pressure is increased at constant temperature?

skelet666 [1.2K]

Answer:

Brown color of the solution decreases

Explanation:

$NO_2$ is brown in color whereas $N_2O_4$ is colorless.

Equilibrium reaction between $NO_2$ and $N_2O_4$ is as follows:

$2NO_2\leftrightharpoons N_2O_4$

As per the Le Chatelier's principle, if pressure of a equilibrium is increased, the equilibrium will shift in the direction having fewer no. of moles of gases.

In the given equilibrium, $NO_2$ side has more no. of moles. So on increasing pressure, equilibrium will shift towards the side of $N_2O_4$ or more formation of $N_2O_4$ will take place.

Therefore, more $NO_2$ will decompose that will decrease the brown color of the solution as $N_2O_4$ is colorless.

6 0

3 years ago

The watt is the standard unit of measurement for?

Crazy boy [7]

Answer:

electrical power. nnnnnnn

3 0

3 years ago

What is the percent yield of CuS for the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? The actua

notka56 [123]

Answer:

(B) 42.1%

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Given: For $Na_2S$

Given mass = 15.5 g

Molar mass of $Na_2S$ = 78.0452 g/mol

Moles of $Na_2S$ = 15.5 g / 78.0452 g/mol = 0.1986 moles

Given: For $CuSO_4$

Given mass = 12.1 g

Molar mass of $CuSO_4$ = 159.609 g/mol

Moles of $CuSO_4$ = 12.1 g / 159.609 g/mol = 0.0758 moles

According to the given reaction:

$Na_2S+CuSO_4\rightarrow Na_2SO_4+CuS$

1 mole of $Na_2S$ react with 1 mole of $CuSO_4$

0.1986 mole of $Na_2S$ react with 0.1986 mole of $CuSO_4$

Available moles of $CuSO_4$ = 0.0758 moles

Limiting reagent is the one which is present in small amount. Thus, $CuSO_4$ is limiting reagent. (0.0758 < 0.1986)

The formation of the product is governed by the limiting reagent. So,

1 mole of $CuSO_4$ gives 1 mole of $CuS$

0.0758 mole of $CuSO_4$ gives 0.0758 mole of $CuS$

Molar mass of $CuS$ = 95.611 g/mol

Mass of $CuS$ = Moles × Molar mass = 0.0758 × 95.611 g = 7.2473 g

Theoretical yield = 7.2473 g

Given experimental yield = 3.05 g

% yield = (Experimental yield / Theoretical yield) × 100 = (3.05/7.2473) × 100 = 42.1 %

Option B is correct.

6 0

3 years ago