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3 years ago

What would be an example of a landform from magma?

Chemistry

2 answers:

mixas84 [53]3 years ago

7 0

The correct answer is (C) Lava plateau.

The explanation:

-Lava plateau is the landform form by volcanic activities , It's formed by highly fluid runny basaltic lava, within quit eruptions.

-It has a low viscosity so that it's a quiet eruption, which contains amount of trapped gases.

- It's flow and cover the original landscape forming lava plateau.

pshichka [43]3 years ago

4 0

The answer is C. lava plateau

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Which would have the lowest input force?

Afina-wow [57]

Answer:

A long lever with the fulcrum as close as possible to the load

Explanation:

If F be the effort , W be the weight , L₁ be the distance of load from fulcrum and L₂ be the distance of effort from the fulcrum ,

Taking moment of force about the fulcrum , we have

W x L₁ = F x L₂

F = W x ( L₁ / L₂ )

F will be minimum when L₁ will be minimum .

Hence fulcrum should be as close as possible to the load.

5 0

3 years ago

Coke is an impure form of carbon that is often used in the in- dustrial production of metals from their oxides. If a sample of c

steposvetlana [31]

Answer:

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

Explanation:

$2CuO+C\rightarrow 2Cu+CO_2$

1 Ton = 907185 grams

Mass of copper oxide = 1.0 Ton = 907185 grams

Moles of copper oxide = $\frac{907185 g}{79.55 g/mol}=11,403.95 moles$

According to reaction, 2 moles of copper oxide reacts with 1 mole of carbon.

Then 11403.95 moles of copper oxide will react with:

$\frac{1}{2}\times 11403.95 mol=5,701.98 mol$ of carbon

Mass of 5,701.98 moles of carbon:

$5,701.98 mol\times 12 g/mol=68,423.75 g$

Mass of coke = x

Mass of carbon = 68,423.75 g

Percentage of carbon in coke = 95%

$95\%=\frac{68,423.75 g}{x}\times 100$

$x=720,250.09 g=0.794 Ton$

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

3 0

3 years ago

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate

vovangra [49]

Answer:

K2 = 61.2 M^-1.S^-1

Explanation:

We complete the question fully:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mol . If the rate constant of this reaction is 6.7M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer is as follows:

The question asks us to calculate the value of the rate constant at a certain temperature, given that it is at a particular value for a particular temperature. We solve the question as follows:

According to Arrhenius equation, the relationship between temperature and activation energy is as follows:

k = Ae^-(Ea/RT)

where, k = rate constant

A = pre-exponential factor

Ea = activation energy

R = gas constant

T = temperature in kelvin

From the equation, the following was derived for a double temperature problem:

ln(k2/k1) = (-Ea/R) * (1/T1 - 1/T2)

We list out the parameters as follows:

T1= (244 + 273.15) K = 517.15 K

T2= (324+ 273.15) K =597.15 K

K1 = 6.7 , K2 = ?

R = 8.314 J/mol K

Ea = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows:

ln(k2/6.7) = (-71000/8.314) * (1/517.15 - 1/597.15)

lnk2 - 1.902 = 8539.8 * 0.000259

lnK2 = 1.902 + 2.21

lnK2 = 4.114

K2 = e^(4.114)

K2 = 61.2

Hence, K2 = 61.2 (M.S)^-1

7 0

3 years ago

Read 2 more answers

Determine the mass in grams of 4.69 x 1021 atoms of barium. (The

Virty [35]

Answer:

1.07 g Ba

Explanation:

Hello there!

In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:

$4.69x10^{21}atoms*\frac{137.327gBa}{6.022x10^{23} atoms} \\\\=1.07gBa$

Best regards!

5 0

2 years ago

The isotope of an atom containing 40 proteins and 51 neutrons suddenly has two neutrons added to it what isotope is created?

aev [14]

The correct answer is (C. zirconium - 93.

7 0

3 years ago