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poizon [28]
3 years ago
8

I really need help a and b

Mathematics
2 answers:
balu736 [363]3 years ago
7 0
PEDMAS for both:
6+4(2+3)²
6+4(5)²
6+4(25)
6+100
106

(6+4)(2+3)
(10)(5)
50

Hope this helps :)
Ivan3 years ago
5 0

Using BEDMAS

a) 6+4(2+3)^2
    6+4(5)^2  - Eliminate addition in bracket
    6+4(25)  - Execute the exponent
    6+100  - Mulitplying
    106 - Addition

b)(6+4)(2+3)
   (10)(5) -Addition in BRACKETS done
   50 - Mulipication

If you found that helpful please rate as "Brainiest" if not comment below :)

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an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.​
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Answer:

\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We need a length of a height.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=5,\ leg=h,\ hypotenuse=20

Substitute:

5^2+h^2=20^2

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h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm

Calculate the area:

A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2

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