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insens350 [35]
4 years ago
8

What is the area of an equilateral triangle with sides of 10 inches and height of 7 inches?

Mathematics
2 answers:
Allisa [31]4 years ago
7 0
Your answer is D. Because the area of a triangle is 1/2bh...10 is your base and 7 is your height ...7*10 =70 then divide by 2... the area is 35
8090 [49]4 years ago
7 0

Answer: D. 35\ in^2

Step-by-step explanation:

Given: Side of equilateral triangle = 10 inches

Height of equilateral triangle= 7  inches

We know that the area of triangle is given by :-

\text{Area}=\frac{1}{2}\times base\times height\\\\\Rightarrow\ \text{Area}=\frac{1}{2}\times10\times7\\\\\Rightarrow\ \text{Area}=35\ in^2

Hence, the area of the given equilateral triangle =35\ in^2

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No it is not a factor

Step-by-step explanation:

Reason for not being a factor is 3x^3-4x^2-4x. 3x3−4x2−4x 3 x 3 - 4 x 2 - 4 x. Factor x x out of 3x3−4x2−4x 3 x 3 - 4 x 2 - 4 x

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It cost Liam $6.10 to send 61 text messages. How much would it cost to send 185 text messages?
vredina [299]

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Step-by-step explanation:

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4 years ago
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5 0
3 years ago
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Find the area (in square feet) of a trapezoid with height h and bases b1 and b2
GalinKa [24]

The area (in square feet) of a trapezoid with height h and bases b1 and b2 is 72 square feet

<h3>Area of a trapezoid</h3>

The formula for calculating the area of the trapezoid is given as:

A = 0.5(b1+b2)h

Given the following

h=12

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Substitute

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A = 72 square feet

Hence the area (in square feet) of a trapezoid with height h and bases b1 and b2 is 72 square feet

Learn more on area of trapezoid: brainly.com/question/1463152

#SPJ1

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