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3 years ago

Evaluate the expression 3mn if m=3 and n=7 please help me solve this problem and explain

Mathematics

2 answers:

Helga [31]3 years ago

7 0

3(3)(7)
3*3=9then 9*7 equals 63.
so the answer is 63

Vinil7 [7]3 years ago

6 0

Substitute 3 into the expression for m, and 7 into it for n. So 3mn = 3(3)(7) = 3 x 21 = 63.

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Help I need step by step answer To the ones circled ASAP!!!!

swat32

Answer:

4. Multiply both sides by -2 => x - 7 = -36, Add 7 to both sides -> x = -29

5. Add 12 to both sides => 28 = 1/4x, then multiply both sides by 4 => 112

x = 112

7. Multiply both sides by 3 => 5x - 2 = 63, add 2 to both sides => 5x = 65,

Divide both sides by 5 -> x = 13

10. Multiply both sides by 6 => 132 = 3x - 6, Add 6 to both sides => 138 = 3x,

Divide both sides by 3 => x = 46

Step-by-step explanation:

3 0

3 years ago

Answers to 1,2,or 3 of these 3

vivado [14]

4)
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5)
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7 0

4 years ago

Pls help convert 1.2675e+37 into scientific notation, im giving 20 points

kicyunya [14]

The answer would be 1.2675 * (10)^37

8 0

3 years ago

The area of the sandbox is 56 2/3 square feet. The width is 8 1/2 feet. What is the length? Hint: Divide area by length

sertanlavr [38]

Answer:

20/3 ft or 6 2/3 ft

Step-by-step explanation:

A = 56 2/3 sq ft

W = 8 1/2 ft

L = ?

A = LW

L = A/W

$L = \dfrac{A}{W}$

$L = \dfrac{56~\frac{2}{3}~sq~ft}{8~\frac{1}{2}~ft}$

Change the mixed numbers into fractions.

$a\frac{b}{c} = \dfrac{ac + b}{c}$

$L = \dfrac{\frac{56 \times 3 + 2}{3}}{\frac{8 \times 2 + 1}{2}}$

$L = \dfrac{\frac{170}{3}}{\frac{17}{2}}$

$L = \dfrac{170}{3} \div \dfrac{17}{2}$

$L = \dfrac{170}{3} \times \dfrac{2}{17}$

$L = \dfrac{170 \times 2}{3 \times 17}$

$L = \dfrac{17 \times 10 \times 2}{3 \times 17}$

$L = \dfrac{10 \times 2}{3}$

$L = \dfrac{20}{3}$

Answer: 20/3 ft or 6 2/3 ft

4 0

4 years ago

What is the sum of the series? 4 ∑k=1 (2k^2−4)

larisa86 [58]

The sum of the series $\sum_{k=1}^{4}\left(2 k^{2}-4\right)$ is 44.

Step-by-step explanation:

The given series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

To find the sum of the series, we need to substitute the values for k in the series.

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]$

Now, simplifying the square terms, we get,

$[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]$

Multiplying the terms,

$[2-4]+[8-4]+[18-4]+[32-4]$

Subtracting the values within the bracket term, we get,

$-2+4+14+28$

Now, adding all the terms, we get the sum of the series,

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

Thus, the sum of the series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

8 0

3 years ago