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anygoal [31]
2 years ago
12

Evaluate the expression 3mn if m=3 and n=7 please help me solve this problem and explain

Mathematics
2 answers:
Helga [31]2 years ago
7 0
3(3)(7)
3*3=9then 9*7 equals 63.
so the answer is 63
Vinil7 [7]2 years ago
6 0
Substitute 3 into the expression for m, and 7 into it for n. So 3mn = 3(3)(7) = 3 x 21 = 63.
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Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

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3 years ago
Will mark branliest!!
zepelin [54]
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6 0
2 years ago
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Line l is parallel to line e in the figure below.
agasfer [191]

Answer: The correct option are as follows;

(1) The triangles are similar because corresponding sides are congruent

(2) The triangles are similar because alternate interior angles are congruent

(3) In the similar triangles, Angle 3 and Angle 6 are corresponding angles

Step-by-step explanation: Please refer to the picture attached for details.

The line i and line e has been drawn and marked as parallel lines. Also two transversal lines m and n have been drawn to intersect in the region between the parallel lines to form two triangles (as shown in the picture).

From the information given, where line e intersects with line n we have angle 1, and where line e intersects with line m we have angle 3, and then the third angle is angle 2.

Furthermore, where line l intersects line m we have angle 6, and where line l intersects line n is angle 4. Also in this second triangle, the third angle is 5.

Upon close observation we would see that Angle 6 is equal to Angle 3, since the transversal m has cut across both parallel lines l and e. Similarly Angle 4 is equal to Angle 1 since the transversal n has cut across parallel lines l and e. Having that Angles 3 and 1 are congruent to Angles 6 and 4, we can conclude that the value of the third angle in one triangle is equal to the that of the third in the second triangle, that is, Angle 2 equals Angle 5. Also, if the angles are similar and the lines l and e are parallel, then the lines formed in both triangles are equal.

So our conclusions are;

The interior angle are alternate angles (Angles 3 and 6, Angles 1 and 4), and the third interior angles are Opposite (Angles 2 and 5 {Opposite angles are equal})

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Answer:

Part C

Look at the circle you created that has point C(the midpoint of AB) as its center and passes through point A.

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