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4 years ago

HELP HURRY I HAVE TO DO THIS TOMORROW PLEASE SHOW WORK

Mathematics

2 answers:

NikAS [45]4 years ago

4 0

For problem number 2: 1,3,5,15

For Problem number 3: 1,2,3,4,5,6,10,12,15,20,30,60

For problem number 4: 1,3,6

For problem number 5: 1,2,3,4,6,12

For problem number 6: 1, 2, 3, 4, 6, 9, 12, 18, 36

For problem number 7: 3

For problem number 8: 4

For problem number 9: 4

For problem number 10: 3

For problem number 11: 5

For problem number 12: 3

Sorry but i didn't answer number 17 and 18

Lookineirs3 years ago

0 0

Jewelery maker has
24 jade beads
30 teak Beads
She has to make necklaces with each necklace having the same number of beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are as follows
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads

The greatest number of tanks is 6 tanks
Step-by-step explanation:
To find the greatest number of tanks that set up to contain 12 angel fish , 24 sword tails and 30 guppies.
We use GCF (Greatest Common Factor) for 12, 24 and 30.
The factors of 12, 24 ,and 30 is

Therefore, the GCF of 12, 24 and 30 is
or
since ) = 12+24+30 fish
therefore, 6 tanks set up with 2 angel fish , 4 sword tails and 5 guppies.

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Please let me know all of the following that applies, thank you in advance.

kramer

Answer: A. EOA and DOS and also

B. SOE and DOA

Step-by-step explanation:

If you look at angle EOA without regarding line OB, you will notice that it is directly opposite to angle DOS.

The same applies for angle SOE and DOA so they are vertically opposite.

3 0

3 years ago

List the common factors of 72 and 36

Alisiya [41]

The gcf of 36 and 72<span> is the largest positive integer that divides the numbers 36 and 72 without a remainder. Spelled out, it is the greatest common factor of 36 and 72. Here you can find the gcf of 36 and 72, along with a total of three methods for computing it. In addition, we have a calculator you should check out. Not only can it determine the gcf of 36 and 72, but also that of three or more integers including thirty-six and seventy-two for example. Keep reading to learn everything about the gcf (36,72) and the terms related to it. kmd</span>

7 0

3 years ago

Parker drove a total distance of 4 and 1 over 2 miles during the months of June and July. If Parker only drove 1 over 8 of a mil

never [62]

Answer: 4 and 1 over 2 ÷ 1 over 8

Step-by-step explanation:

Given that : Total distance drove by Parker =4 and 1 over 2 miles= $4\frac{1}{2}$ miles

Distance drove by Parker each day = 1 over 8 mile= $\frac{1}{8}$ mile

To find the total number of days , we need to divide the total distance by the distance drove by him in each day.

Thus, the number of days he went driving=4 and 1 over 2 ÷ 1 over 8

5 0

3 years ago

Read 2 more answers

A number is chosen at random from the first 100 positive integers. find the probability that the number is divisible by 5. 1/10

Arlecino [84]

The probability that the number chosen is divisible by 5 is; 1/5.

<h3>What is the probability that the number chosen is divisible by 5?</h3>

It follows from the task content that the number of possible outcomes in the probability event is; 100. Additionally, the number of required outcomes is 20 as only 20 numbers are divisible by 5.

Ultimately, the required probability is; 20/100 = 1/5.

Read more on probability;

brainly.com/question/7965468

$SPJ1

8 0

2 years ago

PLEASE HELP ME 30POINTS +BRAINLY

Serga [27]

1) If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is $\frac{1}{6}$ .

If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is $\frac{3}{6}$ = $\frac{1}{2}$ .

<h3>Here are two more examples: </h3>

If a coin is flipped twice, determine the probability that it will land heads both times:

Favorable outcomes: 1 -- HH

Possible outcomes: 4 -- HH, HT, TH, TT

Thus, the probability that the coin will land heads both times is $\frac{1}{4}$ .

If Dan grabs one sock from a drawer containing 3 white socks, 4 blue socks, and 5 yellow socks, what is the probability that he will grab a white sock?

Favorable outcomes: 3 (3 white socks)

Possible outcomes: 12 (3 white socks + 4 blue socks + 5 yellow socks)

Thus, the probability that Dan will grab a white sock is $\frac{3}{12}$ = $\frac{1}{4}$ .

6 0

3 years ago