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pav-90 [236]
3 years ago
5

HELP HURRY I HAVE TO DO THIS TOMORROW PLEASE SHOW WORK

Mathematics
2 answers:
NikAS [45]3 years ago
4 0

For problem number 2: 1,3,5,15

For Problem number 3: 1,2,3,4,5,6,10,12,15,20,30,60

For problem number 4: 1,3,6

For problem number 5: 1,2,3,4,6,12

For problem number 6: 1, 2, 3, 4, 6, 9, 12, 18, 36

For problem number 7: 3

For problem number 8: 4

For problem number 9: 4

For problem number 10: 3

For problem number 11: 5

For problem number 12: 3

Sorry but i didn't answer number 17 and 18

Lookineirs3 years ago
0 0

Jewelery maker has
24 jade beads
30 teak Beads
She has to make necklaces with each necklace having the same number of beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are as follows
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads

The greatest number of tanks is 6 tanks
Step-by-step explanation:
To find the greatest number of tanks that set up to contain 12 angel fish , 24 sword tails and 30 guppies.
We use GCF (Greatest Common Factor) for 12, 24 and 30.
The factors of 12, 24 ,and 30 is



Therefore, the GCF of 12, 24 and 30 is
or
since ) = 12+24+30 fish
therefore, 6 tanks set up with 2 angel fish , 4 sword tails and 5 guppies.




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