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Genrish500 [490]
2 years ago
9

A Kite of Area 255 m2 has one diagonal of length 9m . find the length of the other diagonal

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0

\\ \rm\longmapsto Area=255m^2

\\ \rm\longmapsto LB=255

\\ \rm\longmapsto 9L=255

\\ \rm\longmapsto L=\dfrac{255}{9}

\\ \rm\longmapsto L=28.3m

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The answer to that question is four
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The space shuttle travels at about 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle
forsale [732]

Answer:

3928 hours

Step-by-step explanation:

6 0
2 years ago
What is 79.35 divided by 5
liraira [26]
79.35 divided by 5 equals: <u><em>15.87</em></u>
<em>~~~~~~~~~~~~~~~~~~~~~~~~~~~</em>
To check:
    243
    15.87
<span><u>  x  5.00</u>
</span>     0000
<u>    0000</u>
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5 0
3 years ago
First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

7 0
2 years ago
Synthetic Division <br> -2 | 1 2 -3 1
Tom [10]

Answer:

7

Step-by-step explanation:

I am assuming that the division problem looks like this:

-2|  1   2   -3   1

Going off that assumption, we will work this problem.  The first thing you always do in the execution of synthetic division is to bring down the first number.  Then multiply that number by the one "outside", which is -2, then put that number up under the next number in the line:

-2|  1   2   -3   1

        -2

    1

Now add the 2 and -2 and bring that down as a 0 and multiply the -2 times the 0:

-2|   1   2   -3   1

         -2    0

     1    0

Now add -3 and 0 to get -3 and multiply that -3 times the -2 and put the product up under the next numbe in line;

-2|   1   2   -3   1

          -2   0  6

     1     0   -3

Now add the 1 and the 6 to get the remainder:

7

Read more on Brainly.com - brainly.com/question/12992907#readmore

6 0
2 years ago
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