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Anton [14]
4 years ago
12

Simplify using laws of exponent | -10^5/10^3 |

Mathematics
2 answers:
Vaselesa [24]4 years ago
6 0

Step 1. Use the Quotient Rule: x^a/x^b = x^a-b

|-10^5-3|

Step 2. Simplify 5 - 3 to 2

|-10^2|

Step 3. Simplify 10^2 to 100

|-100|

Step 4. Simplify

100


mixas84 [53]4 years ago
3 0

Solution, \left|-\frac{10^5}{10^3}\right|=100

Steps: \left|-\frac{10^5}{10^3}\right|

\mathrm{Cancel\:}\frac{10^5}{10^3}:\quad 10^2, =\left|-10^2\right|

\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a, =10^2

\mathrm{Refine}, =100

The correct answer is <u><em>100</em></u>

<em>Hope This Helps!!!</em>

<3 - austint1414

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Antonio is starring in the high school play and has lots of family members and
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Answer:

4 Kids 13 Adults

Step-by-step explanation:

13 x 4 = 52   < Adults

4 x 2 = 8  <Kids

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= $60

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8 0
3 years ago
In a multiple regression equation, two independent variables are considered, and the sample size is 30. The regression coefficie
MAXImum [283]

Answer:

Both the variables are important for the regression analysis and cannot be deleted.

Step-by-step explanation:

(1)

The hypothesis for for the testing of coefficient β₁ are:

<em>H</em>₀: β₁ = 0 vs. <em>H</em>ₐ: β₁ ≠ 0

The test statistic is:

t=\frac{b_{1}}{S_{b_{1}}} =\frac{2.815}{0.75}= 3.753

It is provided that H₀ is rejected if <em>t</em> > 2.042.

The test statistic value, <em>t</em> = 3.753 > 2.042.

Thus, the null hypothesis is rejected.

<u>Conclusion:</u>

There is a significant relationship between the regression variable and the dependent variable.

(2)

The hypothesis for for the testing of coefficient β₂ are:

<em>H</em>₀: β₂ = 0 vs. <em>H</em>ₐ: β₂ ≠ 0

The test statistic is:

t=\frac{b_{2}}{S_{b_{2}}} =\frac{-1.249}{0.41}= -3.046

It is provided that H₀ is rejected if <em>t</em> < -2.042.

The test statistic value, <em>t</em> = -3.046 < -2.042.

Thus, the null hypothesis is rejected.

<u>Conclusion:</u>

There is a significant relationship between the regression variable and the dependent variable.

Thus, both the variables are important for the regression analysis and cannot be deleted.

7 0
3 years ago
1- 4% of 79 2- 21% of 65
OleMash [197]
1234 and 79 come before 65
3 0
3 years ago
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
disa [49]

Answer:

z =\frac{50-64}{7}= -2

z =\frac{43-64}{7}= -3

We know that within two deviations from the mean we have 95% of the data from the empirical rule so then below 2 deviation from the mean we have (100-95)/2 % =2.5%. And within 3 deviations from the mean we have 99.7% of the data so then below 3 deviations from the mean we have (100-99.7)/2% =0.15%

And then the final answer for this case would be:

2.5 -0.15 = 2.35\%

Step-by-step explanation:

For this case we have the following parameters from the variable number of motnhs in service for the fleet of cars

\mu = 64, \sigma =7

For this case we want to find the percentage of values between :

P(43< X< 50)

And we can use the z score formula given by:

z = \frac{X-\mu}{\sigma}

In order to calculate how many deviation we are within from the mean. Using this formula for the limits we got:

z =\frac{50-64}{7}= -2

z =\frac{43-64}{7}= -3

We know that within two deviations from the mean we have 95% of the data from the empirical rule so then below 2 deviation from the mean we have (100-95)/2 % =2.5%. And within 3 deviations from the mean we have 99.7% of the data so then below 3 deviations from the mean we have (100-99.7)/2% =0.15%

And then the final answer for this case would be:

2.5 -0.15 = 2.35\%

3 0
3 years ago
-7 + 5 = 19<br> Help PLS
Aloiza [94]

Step-by-step explanation:

19 is the answer I'd don't know why it's so hard

7 0
3 years ago
Read 2 more answers
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