The Y-intercept is a point where the line crosses the Y lines. That means it would be the point where X=0. Then to find the Y-intercept you only need to insert X=0 into the equation. The calculation would be:
<span> 4×+2y=12
4(0) + 2 Y= 12
2Y =12
Y=6</span>
Answer:
<h2>The slope of the line tangent to the function at x = 1 is 2.01 ≅2.</h2>
Step-by-step explanation:
Using the formula of derivative, it can be easily shown that,
where
.
Here we need to show that as per the instructions in the given table.
Δy = f(x + Δx) - f(x) = f(1 + 0.01) - f(1) =
.
In the above equation, we have put x = 1 because we need to find the slope of the line tangent at x = 1.
Hence, dividing Δy by Δx, we get,
.
Let's examine this taking a smaller value.
If we take Δx = 0.001, then Δy =
.
Thus,
.
The more smaller value of Δx is taken, the slope of the tangent will be approach towards the value of 2.
Answer:
we have
Cos (a+b)=Cos aCosb-SinaSinb
for
Cos (a+a)=Cos aCosa-SinaSina=<u>Cos²a-Sin²a</u>
is a required answer.
Answer:
its SAS
Step-by-step explanation: