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Volgvan
3 years ago
11

Suzie solved a linear equation for y. This equivalent equation was her result. y = 7x + 23 Which equations could have been the l

inear equation Suzie manipulated? Check all that apply.
1. y + 7x = 23 2. –7x + y = 23


3. 2y – 14x = 46 4. y – 7x = –23 5. 7x – y = –23
Mathematics
1 answer:
Alika [10]3 years ago
6 0

Answer:

2, 3, 5

Step-by-step explanation:

The question asking for the linear equation Suzie manipulated. The answer should be equal to the starting equation. So, we just need to manipulate the option to y= mx + c format.

1.  y + 7x = 23

y=  -7x +23 (false)

2. . –7x + y = 23

y= 7x + 23 (true)

3. 2y – 14x = 46

2y= 14x+ 46

y= 7x +23 (true)

4. y – 7x = –23

y= 7x - 23 (false)

5. 7x – y = –23

-y= -7x -23

y= 7x + 23 (true)

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According to an​ airline, flights on a certain route are on time ​% of the time. Suppose flights are randomly selected and the n
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Answer:

(a) Explained below.

(b) 0.0294

(c) 0.0173

(d) 0.09827

(e) 0.0452

Step-by-step explanation:

The complete question is:

According to an​ airline, flights on a certain route are on time 80​% of the time. Suppose 25 flights are randomly selected and the number of​ on-time flights is recorded.

​(a) Explain why this is a binomial experiment.

​(b) Find and interpret the probability that exactly 16 flights are on time. ​

(c) Find and interpret the probability that fewer than 16 flights are on time.

​(d) Find and interpret the probability that at least 16 flights are on time.

​(e) Find and interpret the probability that between 14 and ​16 flights, inclusive, are on time.

Solution:

(a)

Let the random variable <em>X</em> be defined as the number of​ on-time flights.

A Binomial experiment has the following properties:

  • There are a fixed number of trials (n).
  • Each trial are independent of the others.
  • Each trial has only two outcomes: Success and Failure
  • Each trial has the same probability of success (p).

If a random variable <em>X</em> is used in an experiment and the experiment has all the above mentioned properties, then the random variable X is known as a binomial random variable.

All of these properties can be confirmed for the random variable <em>X</em>.

Thus, this is a binomial experiment.

(b)

Compute the probability that exactly 16 flights are on time as follows:

P(X=16)={25\choose 16}(0.80)^{16}(0.20)^{25-16}

        =2042975\times 0.0281475\times 0.000000512\\=0.029442375072\\\approx 0.0294

Thus, the probability that exactly 16 flights are on time is 0.0294.

(c)

Compute the probability that fewer than 16 flights are on time as follows:

P(X

                 =0.0000+0.0000+....+0.011777\\=0.0173

Thus, the probability that fewer than 16 flights are on time is 0.0173.

(d)

Compute the probability that at least 16 flights are on time as follows:

P(X\geq 16)=1-P(X

                 =1-0.0173\\=0.9827

(e)

Compute the probability that between 14 and 16 ​flights, inclusive, are on time as follows:

P(14\leq X\leq 16)=\sum\limits^{16}_{x=14}{{25\choose x}(0.80)^{x}(0.20)^{25-x}}

                          =0.004+0.0118+0.0294\\=0.0452

Thus, the probability that between 14 and 16 ​flights, inclusive, are on time is 0.0452.

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