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3 years ago

Arrange the following in ascending order 15, 5, - 10, - 18, - 35

Mathematics

2 answers:

grigory [225]3 years ago

3 0

It’s literally it except it’s the other way around so it’s: -35, -18, -10, 5, 15

lara [203]3 years ago

3 0

Answer:

-35, -18, -10, 5, 15

Step-by-step explanation:

Negative integers have a lesser value than positive integers since it's before 0.

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Nutka1998 [239]

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3 years ago

Read 2 more answers

The dividend is a factor of 60. The divisor is a factor of 18. The quotient is a multiple of 3. Use the numbers to find one poss

Diano4ka-milaya [45]

Answer:

A possible solution is 60/2 = 30

Step-by-step explanation:

The given parameters are;

The dividend is a factor of 60

The divisor is a factor of 18

The quotient is a multiple of 3

The dividend is the amount divided

The dividend is the number that is dividing the dividend

The quotient is the result of the division operation

The given numbers to use are 60, 2, 30, and 18

Therefore one possible solution is 60/2 = 30

The dividend = 60 which is a factor of 60 (60 × 1 = 60)

The divisor = 2 which is a factor of 18 (2 × 9 = 18)

The quotient = 30 which is a multiple of 3 (3 × 10 = 30)

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2 years ago

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$

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3 years ago

Arrange the following in ascending order 15, 5, - 10, - 18, - 35​

Arrange the following in ascending order 15, 5, - 10, - 18, - 35