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3 years ago

What is 2 -2 in 6th grade

Mathematics

1 answer:

Bezzdna [24]3 years ago

3 0

Howdy! My name is Christian and I’ll try and help you with this question!

Date: 9/28/20 Time: 8:38 pm CST

Answer:

Explanation:

2 -2 = 0 :D

Hope this helps you with your question!

Sincerely,

Christian

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how do you find the surface area of a rectangular box with length 10 inches,width 6 inches and height 4 inches

ipn [44]

SA = (Base Area • 2) + (Base Perimeter • Distance)

= (10*6 * 2) + (10 + 10 + 6 + 6 * 4)
= (60 * 2) + (32*4)
=120 + 128
SA = 248 inches squared

4 0

3 years ago

Simplify: 10 m: 20 m : 0.02 km

Arisa [49]

Hope I’m right and hope it helps too

4 0

3 years ago

Write an equation of the form y = mx for the line shown below. If appropriate,

9966 [12]

Answer:

y = - 0.5x

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (2, - 1) ← 2 points on the line

m = $\frac{-1-2}{2-(-4)}$ = $\frac{-3}{2+4}$ = $\frac{-3}{6}$ = - 0.5

The line crosses the y- axis at (0, 0 ) ⇒ c = 0

y = - 0.5x + 0 . that is

y = - 0.5x

6 0

2 years ago

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to