What is 9.52 rounded to the nearest tenth?

Mathematics

1 answer:

Serhud [2]3 years ago

8 0

Answer:

9.5

Step-by-step explanation:

When rounding to the nearest tenth, check to see what the hundredths place value is.

If it is 0.05 or greater, we will round the tenths place up one.

If not, the tenths place will remain the same.

Since 9.52 has a hundredths place value of 0.02, we will keep the same tenths place value.

So, the correct answer is 9.5

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Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

$x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)$

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize $x^2-\frac13$ as yet another difference of squares: