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2 years ago

14

binks need to raise at least $3600. He was given $200 and plans to save $50 per week. Select all the inequalities in this situat

ion where , n, is the number of weeks.

1 answer:

-BARSIC- [3]2 years ago

6 0

Answer:

First of read all formulas

Step-by-step explanation:

Calculate 50 *7 and add 350 and 200

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Is (1,-4) a solution to the equation y=-2x?<br> Yes or no? Please help /:

Elden [556K]

No it is not, the solution would need to be (2,-4) in order to satisfy the equation y = -2x -- like so -4 = -2(2)

-4 = -4, otherwise the equation won't be satisfied.

4 0

2 years ago

Read 2 more answers

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$

8 0

3 years ago

Marty ate 1/4 of his pizza and Luis ate 1/3 of his pizza. Marty ate more pizza than Luis. Is that possible?

Nataly_w [17]

Of course.

You can only say for sure that 1/4 of a whole thing is less than 1/3 of a whole thing
if the whole things are equal size.

If Marty's pizza was 1/3 bigger than Luis' pizza, then they both ate the same amount.
If Marty's was MORE than 1/3 bigger than Luis', then Marty ate more pizza.

8 0

3 years ago

Read 2 more answers

A cylindrical piece of iron pipe is shown below. The wall of the pipe is 0.75 inch thick, and the pipe is open at both ends: The

const2013 [10]

Answer:

It's 398

Step-by-step explanation.

Diameter of 8.

height of 12.

8 - .75 - .75= 6.5

6.5/2 = 3.25

3.25 x 3.25 x 12 x 3.14 = 397.995

round to the nearest whole number and you get

398

Take the diameter (8) an subtract is by both sides of the walls (0.75 each wall) that gives you 6.5. Take that 6.5 and half that, because you need to have the radius to solve volume problems, giving you 3.25. Then multiply 3.25 by 3.25 together ( I know it seems redundant but it just works easier this way) This gives you 10.5625. After that take 10.5625 then multiply it into 12, being the height, which gives you 126.75. Finally take 126.75 and multiply that into 3.14 (pie) giving you the answer.

3 0

3 years ago

What is the form of the two squares identity?

zvonat [6]

Answer:

D

Step-by-step explanation:

Consider all options:

A. False, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ab-cd)^2+(ac+bd)^2=a^2b^2-2abcd+c^2d^2+a^2c^2+2abcd+b^2d^2=\\ =a^2b^2+c^2d^2+a^2c^2+b^2d^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2\neq a^2b^2+c^2d^2+a^2c^2+b^2d^2$

B. False, because

$(a^2-b^2)(c^2+d^2)=a^2c^2+a^2d^2-b^2c^2-b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2-b^2c^2-b^2d^2\neq a^2c^2+b^2d^2+a^2d^2+b^2c^2$

C. False, because

$(a^2+b^2)(c^2-d^2)=a^2c^2-a^2d^2+b^2c^2-b^2d^2\\ \\(ac+bd)^2-(ad+bc)^2=a^2c^2+2abcd+b^2d^2-a^2d^2-2abcd-b^2c^2=\\=a^2c^2+b^2d^2-a^2d^2-b^2c^2\\ \\a^2c^2-a^2d^2+b^2c^2-b^2d^2\neq a^2c^2+b^2d^2-a^2d^2-b^2c^2$

D. True, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2= a^2c^2+b^2d^2+a^2d^2+b^2c^2$

6 0

3 years ago