She needs a score of 89 for it to be an average of 91.00
Answer:
3
Step-by-step explanation:
<u>3</u>,6,9,12,15,18,21,<u><em>24</em></u>
<u>3</u>,6,9,12,<em><u>15,</u></em>18,21,24
Answer:
A: 19:26 B:7:8 C:26:45
Step-by-step explanation:
<u>Question A</u>
First to find the ratio between the boys and girls you would add all of the different groups with boys and girls. This would be done by,
<u>Boys</u>
9+10=19
<u>Girls</u>
12+14=26
Now that you have the total number of boys and girls you make this ratio,
19:26
That is the final answer
<u>Question B</u>
For this it is very similar to the boys to girls ratio. You still add the total on each side and then form a ratio. From before you would start by adding both of the different sides which would be done by,
<u>Fifth Graders</u>
12+9=21
<u>Sixth Graders</u>
14+10=24
Now that you have the total number of both of the different grades you make this ratio,
21:24
You can simplify this by finding the lowest common factor which would be
7:8
<u>Question C</u>
To answer this it is very similar to the first two but instead you will find one group and all of the groups to form the ratio. Now you need to add all of the people in each of the groups.
<u>Girls</u>
12+14=26
<u>All</u>
12+9+14+10=45
Now with the total number of both you will form a ratio
26:45
This is your final answer because you cant simplify this any further
Step-by-step explanation:
(a)
Using the definition given from the problem
![f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\](https://tex.z-dn.net/?f=f%28A%29%20%3D%20%5C%7Bx%5E2%20%20%5C%2C%20%3A%20%5C%2C%20x%20%5Cin%20%5B0%2C2%5D%5C%7D%20%3D%20%5B0%2C4%5D%5C%5Cf%28B%29%20%3D%20%5C%7Bx%5E2%20%20%5C%2C%20%3A%20%5C%2C%20x%20%5Cin%20%5B1%2C4%5D%5C%7D%20%3D%20%5B1%2C16%5D%5C%5Cf%28A%29%20%5Ccap%20f%28B%29%20%3D%20%5B1%2C4%5D%20%20%3D%20f%28A%20%5Ccap%20B%29%5C%5C)
Therefore it is true for intersection. Now for union, we have that
![A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]](https://tex.z-dn.net/?f=A%20%5Ccup%20B%20%3D%20%5B0%2C4%5D%5C%5Cf%28A%5Ccup%20B%20%29%20%3D%20%5B0%2C16%5D%5C%5Cf%28A%29%20%3D%20%5B0%2C4%5D%5C%5Cf%28B%29%3D%20%5B1%2C16%5D%5C%5Cf%28A%29%20%5Ccup%20f%28B%29%20%3D%20%5B0%2C16%5D)
Therefore, for this case, it would be true that 
.
(b)
1 is not a set.
(c)
To begin with
Therefore
Now, given an element of 
it will belong to both sets, therefore it also belongs to 
, and you would have that
, therefore 
.
(d)
To begin with 
, therefore
Answer:
the angle would be 1/2 i did this problem before and got it correct
Step-by-step explanation:
