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2 years ago

"The sum of twice a number and 7"

Mathematics

1 answer:

Elden [556K]2 years ago

4 0

Sorry if this is wrong. Expression <<<2a +7

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i need to find the zeros by factoring but im stuck plss help me i think the zeros may be 0, 1, -4, and 4 but i dont know how to

Sveta_85 [38]

This should help you on how to get the zeros and the answer for the bottom question is A

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1 year ago

Read 2 more answers

How does the division rule for exponents help in understanding why anything to the zero power is 1?

Nookie1986 [14]

In the division rule you subtract the exponents when dividing numbers with the same base. One rule for exponents is that exponents add when you have the same base. This works for any number x that you want to plug in except for x = 0,because 0/0 is indeterminate (it is like dividing zero by zero). No matter what number we use when it is raised to the zero power it will always be 1.

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3 years ago

Find the multiplicative inverse of -2 in mod 7

Elis [28]

Answer:

So something mod 7 is -2
Lets consider what mod does as a commands: If you have 7 and then mod it by 2 ie 7%2 you get 1
Essentially mod is seeing how many times a # goes into the other number and finding the remainder.
In this case we want the remainder of 2: -8%3 =-2
note there is also a mathematical procedural way to solve this.
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6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B9%7D%20" id="TexFormula1" title=" \sqrt[3]{9} " alt=" \sqrt[3]{9} " align=

Art [367]

Answer:

$\sqrt[3]{9}= 2.08008...$

Step-by-step explanation:

I used a calculator but 9 is not a perfect cube

7 0

3 years ago

consider a wire 2 ft long cut into two pieces. one piece forms a circle with radius r and the other forms a square with side len

makkiz [27]

The formula for the radius r in terms of x . and for the maximum areas is x=2/ $\pi$ +4

Given that,

y forms a circle of radius r

y=2 $\pi$ r

r=y/2 $\pi$

(2-y)- forms Square Side x

(2-y) = 4x

x=(2-y)/4

Now Sum of Area's=Area of Square +Area of Circle

Sum = $\pi$ r² + x²

Substitute the r and x values in above equation,

A(y)= y²/4 $\pi$ +(y-2)²/ 16

To maximize Area A(y)

A'(y)= 0

2y/4 $\pi$ + 2(y-2)/16 =0

y/2 $\pi$ + (y-2)/8 =0

y = 2 $\pi$ / $\pi$ +4

Y max will be max, x to be maximum.

for maximum sum of areas,

x=2/ $\pi$ +4

Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/ $\pi$ +4

Learn more about Area :

brainly.com/question/28642423

#SPJ4

4 0

1 year ago