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IRINA_888 [86]
3 years ago
6

My math problem is: X/8 + 6 = -8

Mathematics
1 answer:
lora16 [44]3 years ago
8 0
X=-112 because u do x/8+6=-8
-6 -6
x/8=-14
×8 ×8
x=-112
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Graph the circle (x-8)^2 + (y+5)^2 = 4
Kobotan [32]

Answer:

The answer to your question is See the attachment

Step-by-step explanation:

Equation

             (x - 8)² + (y + 5)² = 4

Process

1.- Write the standard equation of the circle

            (x - h)² + (y - k)² = r²

2.- Find the center

The center are the letters h and k

      h = 8  k = -5

3.- Find the radius

      r = 2

4.- Graph the circle ( i will use geogebra)

See below

3 0
3 years ago
Is 5 in the solution set of x+3>8
Irina-Kira [14]

Answer:

It 5 would not be x

Step-by-step explanation:

If 5 was x, then it would be equivalent, because 5+3 = 8. I hope this helped.

8 0
3 years ago
Read 2 more answers
Wich measurements is not precise 982g or 980g
gavmur [86]

Answer:

982 g

Step-by-step explanation:

Hopefully this helps you :)

8 0
3 years ago
Suppose that the relation G is defined as follows.
Serga [27]

G:{3,4,6}->{0,9}

The pairs represent the input (first number in each pair) and the result (second nu.ber in each pair) for the relation G. for example G(3)=9.

The domain is the set of values that the relation can act upon. The range is the set of the values the results can take

6 0
3 years ago
A drink is made by mixing 650 ml of water with 150 ml of fruit juice.
Luda [366]
<h2>○=> <u>Correct answer</u> :</h2>

\boxed{\color{hotpink}\tt18.75\%} of the drink is fruit juice

<h3>○=> <u>Steps to derive correct answer</u> :</h3>

Quantity of water in a drink = 650 ml

Quantity of fruit juice in a drink = 150 ml

Total quantity of both items in the drink :

=\tt 650 + 150

\color{plum}=\tt 800 \: ml

Thus, the total quantity of both items in the drink = 800 ml

Let the percentage of of fruit juice in the drink be x%.

Which means :

=  \tt\frac{x}{100}  \times 800 = 150

= \tt \frac{x \times 800}{100}  = 150

=\tt  \frac{800x}{100}  = 150

=\tt 8x = 150

=\tt x =  \frac{150}{8}

\hookrightarrow\color{plum} \bold{x = 18.75\%}

Then, the percentage of water in the drink :

= \tt100 - 18.75

\color{plum}= \tt81.25\%

Thus, the percentage of water in the drink = 81.25%

<h3>○=> <u>Therefore</u> :</h3>

▪︎Percentage of fruit juice in the drink = 18.75%

▪︎Percentage of water in the drink = 81.75%

8 0
3 years ago
Read 2 more answers
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