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3 years ago

6

My math problem is: X/8 + 6 = -8

1 answer:

lora16 [44]3 years ago

8 0

X=-112 because u do x/8+6=-8
-6 -6
x/8=-14
×8 ×8
x=-112

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Expand and simpifly 2(x+7) + 3(x+1)

MaRussiya [10]

Answer: 5x+17

Step-by-step explanation:

2(x+7) + 3(x+1)

2x+14 + 3x+3

5x+17

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2 years ago

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The linear equation y = mx + b contains the point (4, -2) and is perpendicular to the

xenn [34]

A linear equation is represented as: $y = mx + b$ .

The equation of the line is: $y =3x - 14$

First, we calculate the slope (m) of $6x + 18y = 11$

Make y the subject

$18y = -6x + 11$

Divide by 18

$y = -\frac{1}{3}x + \frac{11}{18}$

In $y = mx + b$

$m \to$ slope

So, the slope of $y = -\frac{1}{3}x + \frac{11}{18}$ is:

$m = -\frac 13$

Since, the line is perpendicular to $6x + 18y = 11$

The slope of the line is:

$m_1 = -\frac{1}{m}$

So, we have:

$m_1 = -\frac{1}{-1/3}$

$m_1 = 3$

The line passes through (4,-2).

So, the equation is:

$y =m(x - x_1) + y_1$

This gives:

$y =3(x - 4) -2$

$y =3x - 12 -2$

$y =3x - 14$

Hence, the linear equation is:

$y =3x - 14$

Read more about at:

brainly.com/question/11897796

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3 years ago

Siri, who is not yet 22 years old, is five years older than Lily. Write and solve an

Zolol [24]

Answer:

22-5= L

L = 17

Step-by-step explanation:

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2 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

2 years ago

Two towns that are 31.5 km apart are 3 cm apart on a map. what is the scale of the map?

VLD [36.1K]

<u>Answer:</u>

1 cm : 10.5 km

<u>Step-by-step explanation:</u>

We are given that two towns are 31.5 km in real and are 3 cm apart on a map and we are to find the scale of the map.

For this, we can use the ratio method.

$\frac { 3 cm } { 1 c m } = \frac { 3 1 . 5 k m } { x }$

$x = \frac { 3 1 . 5 \times 1 } { 3 }$

$x = 1 0 . 5$

Therefore, the scale of the map would be 1 cm : 10.5 km.

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3 years ago

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