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1 year ago

Marissa drew and labeled 4 triangles on grid paper as shown below. Which triangle appears to be an obtuse triangle

Mathematics

1 answer:

Pachacha [2.7K]1 year ago

5 0

The triangle that must appear to be obtuse mmust have one of its angle to be greater than 90 but less than 180 degrees:

<h3>What are obtuse triangles?</h3>

Obtuse triangles are triangles that has one of theor angles to greater than 90 degrees.

Most obtuse triangles has two acute angles (angles less than 90 degrees) and a obtuse angle (angles between 90 and 180 degrees)

Hence the triangle that must appear to be obtuse mmust have one of its angle to be greater than 90 but less than 180 degrees:

Learn more on obtuse triangle here: brainly.com/question/3250447

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Will reward brainliest

LuckyWell [14K]

Answer:

Step-by-step explanation:

Volume of first container = 48 cm³

πr²h = 48 cm³

Second container:

height = (2/3)h

Volume of second container=

$=\pi *r^{2}*(\frac{2}{3}*h)\\\\=\frac{2}{3}*\pi *r^{2}*h\\\\$

=(2/3)* first container's volume {πr²h = 48 cm³}

$=\frac{2}{3}*48\\\\=2*16\\\\$

= 32 cm³

6 0

3 years ago

Rectangle 1 has length x and width y. Rectangle 2 is made by multiplying each dimension of Rectangle 1 by a factor of k, where k

tresset_1 [31]

Answer:

a) Similar

b) Perimeter of rectangle 2 is k times the Perimeter of rectangle 1 (Proved Below)

c) Area of rectangle 2 is k^2 times the Area of rectangle 1 (Proved Below)

Step-by-step explanation:

Given:

Rectangle 1 has length = x

Rectangle 1 has width = y

Rectangle 2 has length = kx

Rectangle 2 has width = ky

(a) Are Rectangle 1 and Rectangle 2 similar? Why or why not?

Rectangle 1 and Rectangle 2 are similar because the angles of both rectangles are 90° and the sides of Rectangle 2 is k times the sides of Rectangle 1. So sides of both rectangles is equal to the ratio k.

(b) Write a paragraph proof to show that the perimeter of Rectangle 2 is k times the perimeter of Rectangle 1.

Perimeter of Rectangle = 2*(Length + Width)

Perimeter of Rectangle 1 = 2*(x+y) = 2x+2y

Perimeter of Rectangle 2 = 2*(kx+ky) = 2kx + 2ky

= k(2x+2y)

= k(Perimeter of Rectangle 1)

Hence proved that Perimeter of rectangle 2 is k times the perimeter of rectangle 1.

(c) Write a paragraph proof to show that the area of Rectangle 2 is k^2 times the area of Rectangle 1.

Area of Rectangle = Length * width

Area of Rectangle 1 = x * y

Area of Rectangle 2 = kx*ky

= k^2 (xy)

= k^2 (Area of rectangle 1)

Hence proved that area of rectangle 2 is k^2 times the area of rectangle 1.

4 0

3 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$