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1 year ago

Marissa drew and labeled 4 triangles on grid paper as shown below. Which triangle appears to be an obtuse triangle

Mathematics

1 answer:

Pachacha [2.7K]1 year ago

5 0

The triangle that must appear to be obtuse mmust have one of its angle to be greater than 90 but less than 180 degrees:

<h3>What are obtuse triangles?</h3>

Obtuse triangles are triangles that has one of theor angles to greater than 90 degrees.

Most obtuse triangles has two acute angles (angles less than 90 degrees) and a obtuse angle (angles between 90 and 180 degrees)

Hence the triangle that must appear to be obtuse mmust have one of its angle to be greater than 90 but less than 180 degrees:

Learn more on obtuse triangle here: brainly.com/question/3250447

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Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)

Fantom [35]

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Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .

Hence, $\tan(x)$ would be:

$\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}$ .

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