Step-by-step explanation:
Using the Intermediate Value Theorem, the following is applied:
"If f(x) is a continuous on interval [a,b] and we have two points f(a) and f(b) then there must be some value c such that f(a)<f(c)<f(b).
So here there must be a c such that

Note: F(c)=0, the questions that the function have a solution between 0 and 1, so that means we must have some value, c such that f(c)=0 that exists
Next, plug in the x values into the function


Since cubic functions are continuous and -4<0<4, then there is a solution c that lies between f(0) and f(1)
Answer: (16, 24)
Step-by-step explanation:
Hope this helps , good luck with the rest!
8x^2 - 16x - 15 = 0
x = [ -(-16) +/- sqrt((-16)^2 - 4*8*-15) / ] 2*8
= 2.696, -0.696
Multiple-3(x+0.6) and 6(x+2.4) you will get -3x-1.8=6x+14.4 then you add -3x + 6x you will get -9x=14.4+1.8 you add 14.4+1.8 that will give you 16.2 then divide that by -9