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weqwewe [10]
3 years ago
13

What is the sum of 12 – 5i and –3 + 4i? –16 + 63i 9 – i 9 – 9i 15 – 9i

Mathematics
2 answers:
iogann1982 [59]3 years ago
4 0

Answer:

B. 9 - i

Step-by-step explanation:

Edge 2020

Svetach [21]3 years ago
3 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{9 - i}}}}}

Step-by-step explanation:

\sf{12 - 5i + ( - 3 + 4i)}

When there is a ( + ) in front of an expression in parentheses, there is no need to change the sign of each term. That means, the expression remains the same. Just remove the parentheses

\longrightarrow{ \sf{12 - 5i - 3 + 4i}}

Collect like terms

\longrightarrow{ \sf{ 12 - 3 - 5i + 4i}}

Subtract 3 from 12

\longrightarrow{ \sf{9 - 5i + 4i}}

Collect like terms

\longrightarrow{ \sf{9 - i}}

Hope I helped!

Best regards! :D

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Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
Find the opposite of 1/3 and of -7/12
dimaraw [331]
Opposite number is the same number with the opposite sign:

So the opposite of \frac{1}{3} is -\frac{1}{3}, since the original number is positive

opposite of - \frac{7}{12} is \frac{7}{12}, since the original number is negative

3 0
3 years ago
Read 2 more answers
Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.
zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

__

b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

  = 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

__

c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

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larisa [96]

Answer:

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Step-by-step explanation:

7 0
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A camp stove that was $175.99 is now $155.99. what percent discount are you getting?
Flura [38]
Your getting a $20 dollar discount
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