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lukranit [14]
3 years ago
6

Find two consecutive numbers with a product of 121

Mathematics
1 answer:
Crank3 years ago
6 0
One number: x
Its consecutive:  x + 1

Product:

x(x+1)=121
x² + x - 121 = 0

Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485

As square root of 485 is not integer, do not exist two consecutive numbers with product of 121
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<span>Add 70 to each side of the equation. -70 + 70 + -8y = 2 + 70
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Divide each side by -8.
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Hope I Helped!!!
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3 years ago
This is my question!<br> Please help answer!!!
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Stels [109]

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44

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4 0
3 years ago
A software company is releasing one of their products on a CD. The manufacturer charges a $5,500 setup fee and $1.00 per CD. App
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6 0
3 years ago
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An item is regularly priced at $60 . Jessica bought it on sale for 65% off the regular price. How much did Jessica pay?
adoni [48]

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6 0
3 years ago
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