Answer:
78
Step-by-step explanation:
Evaluate 6 (2 x^2 - 5) where x = -3:
6 (2 x^2 - 5) = 6 (2×(-3)^2 - 5)
Hint: | Evaluate (-3)^2.
(-3)^2 = 9:
6 (2×9 - 5)
Hint: | Multiply 2 and 9 together.
2×9 = 18:
6 (18 - 5)
Hint: | Subtract 5 from 18.
| 1 | 8
- | | 5
| 1 | 3:
6×13
Hint: | Multiply 6 and 13 together.
6×13 = 78:
Answer: 78
Answer:
a

b

c

Step-by-step explanation:
Generally the size of the sample sample space is mathematically represented as

Where N is the total number of objects available and r is the number of objects to be selected
So for a, where N = 19 and r = 8



For b Where N = 25 and r = 3



For c Where N = 23 and r = 2



Answer:
12
Step-by-step explanation:
Use the Pythagorean theorem which is a^2 + b^2 = c^2
c is hypotenuse and a and b are the legs
we need to find a^2 so
a^2 + 16^2 = 20^2
a^22 + 256 = 400
then subtract 256 from 400
a^2 = 144
square root 144
= 12
Answer:
The slope of the function is 4040 which represents the monthly fee to remain a member.
Step-by-step explanation:
i promise its right
9514 1404 393
Answer:
C, A, A
Step-by-step explanation:
In general, you ...
- identify the coefficients of one of the variables
- swap them, and negate one of them
- multiply the corresponding equations by the "adjusted" coefficients.
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In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:
multiply equation 2 by -4 . . . (eliminates x)
Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:
multiply equation 1 by 3 . . . (eliminates y)
These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.
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The other problems are worked in a similar fashion.