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2 years ago

6

Find two consecutive numbers with a product of 121

1 answer:

Crank2 years ago

6 0

One number: x
Its consecutive: x + 1

Product:

x(x+1)=121
x² + x - 121 = 0

Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485

As square root of 485 is not integer, do not exist two consecutive numbers with product of 121

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pav-90 [236]

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3 years ago

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2/3 x 1/5 = 2/15<br><br> Needs points pls helpp

Alina [70]

Answer:

sure!

Step-by-step explanation:

1

Multiply the numbers

2

3

⋅

1

5

=

2

1

5

2

3

5

=

2

1

5

Divide the numbers

2

3

5

=

2

1

5

2

1

5

=

2

1

5

Result

2

1

5

=

2

1

5

5 0

3 years ago