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hram777 [196]
3 years ago
15

Choose the polynomial that is written in standard form.

Mathematics
2 answers:
galina1969 [7]3 years ago
7 0

Answer:

C) -3x^8y^2+9x^2y+10x^2

Step-by-step explanation:

Since, a polynomial having the descending order of degrees of the monomial is called the standard polynomial,

Also, the degree of a term in the polynomial is the total sum of the power of all variable in that term,

In option a),

2x^2y^2 + 3x^4y + 10x^6

Order of degree is,

4, 5, 6

Which is not in the descending order,

⇒ It is not a standard polynomial.

In option b),

4x4y^2 + 6x^3y^5 + 10x

Order of degree is,

5, 8, 1

Which is not in the descending order,

⇒ It is not a standard polynomial.

In option c),

-3x^8y^2 + 9x^2y + 10x^2

Order of degree is,

11, 3, 2

Which is in the descending order,

⇒ It is a standard polynomial.

In option d),

-7x^6y^2 + x^3y^8 + 10x^2

Order of degree is,

8, 11, 2

Which is not in the descending order,

⇒ It is not a standard polynomial.

OleMash [197]3 years ago
4 0
The degrees of the terms are ...
  a) 4, 5, 6
  b) 6, 8, 1
  c) 10, 3, 2
  d) 8, 11, 2

The polynomial that has terms in decreasing order of degree is
  c) -3x⁸y² +9x²y +10x²
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0.5

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Step-by-step explanation:

The Canada Urban Transit Association has reported that the average revenue per passenger trip during a given year was $1.55. If we assume a normal distribution and a standard deviation of 5 $0.20, what proportion of passenger trips produced a revenue of Source: American Public Transit Association, APTA 2009 Transit Fact Book, p. 35.

a. less than $1.55?

b. between $1.15 and $1.95? c. between $1.35 and $1.75? d. between $0.95 and $1.55?

Given that :

Mean (m) = 1.55

Standard deviation (s) = 0.20

a. less than $1.55?

P(x < 1.55)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

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p(Z < 0) = 0.5 ( Z probability calculator)

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P(x < 1.15)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.15 - 1.55) / 0.20 = - 2

p(Z < - 2) = 0.02275 ( Z probability calculator)

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USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

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p(Z < - 2) = 0.97725 ( Z probability calculator)

0.97725 - 0.02275 = 0.9545

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P(x < 1.35)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

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p(Z < - 2) = 0.15866 ( Z probability calculator)

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USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

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0.84134 - 0.15866 = 0.68268

d. between $0.95 and $1.55?

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USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (0.95 - 1.55) / 0.20 = - 3

p(Z < - 3) = 0.0013499 ( Z probability calculator)

P(x < 1.55)

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Z = (x - m) / s

Z = (1.55 - 1.55) / 0.20 = 0

p(Z < 0) = 0.5 ( Z probability calculator)

0.5 - 0.0013499 = 0.4986501

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