the weight of four puppies are shown below which list show these weights in order from least to greatest

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Nastasia [14]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

Revathi's age is 1/3 of her mother's age. If their difference in age is 24 years, find Revathi's age.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

Given,

Mother's age = x
Revathi's age = 1/3 x = ?
Difference in their age = 24 years ⇨ x - 1/3 x = 24.

Now, let's solve this question using the above equation which we just formed.

$\sf \: x - \frac{1}{3}x = 24 \\$

Combine x and $\sf\:-\frac{1}{3}x$ to get $\sf\frac{2}{3}x$ .

$\sf\frac{2}{3}x=24 \\$

Multiply both sides by $\sf\frac{3}{2}$ , the reciprocal of $\sf\frac{2}{3}$ .

$\sf \: x=24\times \left(\frac{3}{2}\right)$

Express $\sf24\times \left(\frac{3}{2}\right)$ as a single fraction.

$\sf \: x=\frac{24\times 3}{2} \\$

Multiply 24 and 3 to get 72.

$\sf \: x=\frac{72}{2} \\$

Divide 72 by 2 to get 36.

$\boxed{ \bf \: x=36 }$

We now have the age of Revathi's mother (x) = 36 years. Now, let's find Revathi's age ⇨ $\sf\:(\frac{1}{3}x)$

$\rightarrow \sf \: \frac{1}{3} x \\ \rightarrow \sf \: \frac{1}{3} \times 36 \\ \rightarrow \sf \: \frac{1}{ \bcancel 3} \times \bcancel{36} \\ \rightarrow \sf \:1 \times 12 \\ = \boxed{\boxed{\bf \: 12}}$

So, Revathi is 12 years old.

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3 years ago

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The function — is used to model the height of an object projected in the air, where h(t) is the height in meters and t is the ti

MissTica

The answer choice which represents the domain and range of the function h(t) as given in the task content in which case, values are rounded to the nearest hundredth is; Domain: [0, 3.85] and Range: [0, 18.05].

<h3>What are the domain and range of the function as given in the task content?</h3>

It follows from convention that the domain of a function simply refers to the set of all possible input values for that function.

Also, the range of a function is the set of all possible output values for such function.

On this note, by observing the graph in the attached image, it follows that the Domain of the function in discuss is; [0, 3.85].

While the range is the difference between the minimum and maximum height attained and can be computed as follows;

At minimum height, t = 0; hence, h(t) = 0.

At maximum height; h'(t) = 0 where h'(t) = h'(t)=-9.74t+18.75 and hence, t = 1.92.

Hence, h(1.92) = 18.05.

The range is therefore; [0, 18.05].

Read more on domain and range;

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