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3 years ago

165 is what percent of 433? set up a proportion and solve

Mathematics

1 answer:

seropon [69]3 years ago

6 0

Answer:

38.1%

Step-by-step explanation:

Divide 165 by 433

165/433 = 0.381

Multiply the answer by 100

0.381 x 100 = 38.1

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Solve for L: P = 2L + 2W

natulia [17]

$P = 2L + 2W\\2L=P-2W\\L=\dfrac{P-2W}{2}$

3 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

bearhunter [10]

Answer:

(a) ∠HIK and ∠GFD

Step-by-step explanation:

In this geometry, there are only two pairs of alternate exterior angles:

∠HIK and ∠GFD

∠JIK and ∠EFD

Of these, only the first pair is among the answer choices.

Alternate exterior angles are ones that are outside the parallel lines, and on opposite sides of the transversal.

7 0

3 years ago

Casey has a job doing valet parking. Casey makes an hourly rate of $4.55 per hour plus tips. Last week Casey worked 26 hours and

qaws [65]

The answer is D. $780.25

In this particular case, you just need to find the difference between what Casey earn hourly with his total earning..

The hourly wage that Casey earned in 26 hours:
$ 4.55 x 26 = 118.3

The total amount that casey earned in 26 hours:
$898.55

So, the amount that Casey earned through tips:
$898.55 - $118.3 = $780.25

7 0

3 years ago

) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.

yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the 0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= $\dfrac{1}{2}$

The length of bits : n = 10

Let X = Number of getting ones.

Then , $X \sim Bin(n=10,\ p=\dfrac{1}{2})$

Binomial distribution formula : $P(X=x)=^nC_x p^x q^{n-x}$ , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , $p=q=\dfrac{1}{2}$

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

$P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}$

$=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}$

$=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})$

$=(\dfrac{1}{2})^{10}(210+252)$

$=(0.0009765625)(462)$

$=0.451171875\approx0.4512$

Hence, the probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0

4 years ago

<img src="https://tex.z-dn.net/?f=%20Simplify%3A%20%5C%3A%2018%20%5Cdiv%2016%20%2B%20%5B8%20%5C%7B16%20%5Cdiv%20%2810%20-%20%5Co

tester [92]

<h3>Simplify :</h3>

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}$

Simplifying vinculum bar 

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}$

Simplifying parentheses brackets

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}$

Simplifying curly brackets 

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \dfrac{16}{4} \bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \cancel{\dfrac{16}{4}} \bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \times 4\bigg]}}}}$

Simplifying square brackets 

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \times 4\bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + 32}}}}$

According to BODMAS rule simplifying devision 

${:\implies{\small{\sf{18 \div 16 + 32}}}}$

${:\implies{\small{\sf{ \dfrac{18}{16} + 32}}}}$

${:\implies{\small{\sf{{\cancel{\dfrac{18}{16}} + 32}}}}}$

${:\implies{\small{\sf{ 1.125 + 32}}}}$

Now, according to BODMAS rule simplifying addition

${:\implies{\small{\sf{ 1.125 + 32}}}}$

${:\implies{\small{\sf{33.125}}}}$

${:\implies{\underline{\boxed{\pmb{\sf{Answer = 33.125}}}}}}$

∴ The answer is 33.125.

 $\underline{\rule{200pt}{2.5pt}}$ 

3 0

2 years ago

Read 2 more answers