x= 9
y= 9
4x -2y= 18.................equation 1
-4x + 2y= -18...............equation 2
From equation 1
4x= 18 + 2y
x= 18 + 2y/4
substitute 18+2y/4 for x in equation 2
-4(18+2y/4) -2y= 18
-(18+2y)-2y= 18
-18-2y-2y= 18
-18+4y= 18
4y= 18+18
4y= 36
y= 36/4
y= 9
Substitute 9 for y in equation 1
4x-2y= 18
4x-2(9)= 18
4x-18= 18
4x= 18+18
4x= 36
x= 36/4
x= 9
Hence the value of x is 9 and the value of y is 9
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Answer:
The width of the football field is 160 feet.
The length of the football field is 360 feet.
Step-by-step explanation:
Let w represent width of the football field.
We have been given that the length is 200 ft more than the width, so the length of the field would be 
.
We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:
Let us solve for w.
Therefore, the width of the football field is 160 feet.
Upon substituting in expression , we will get length of field as:
Therefore, the length of the football field is 360 feet.
Answer:
a) A(x) = 90*x/2 - x²/2
b) A(max) = 1012.5 m²
Step-by-step explanation:
L = 90 meters of fencing
Rectangular area is
A(r) = x*y . where x and y are the sides of the rectangle
the perimeter is ( we are going to fence only 3 sides, then)
x + 2*y = 90 or . y = ( 90 - x ) /2
Area as a function of x is:
A(x) = x * ( 90 - x)/2
A(x) = 90*x/2 - x²/2
Tacking derivatives on both sides of the equation:
A´(x) =45 - 2*x/2 A´(x) =45 - x
A´(x) = 0 . 45 - x = 0 . x = 45 . meters
and . y = ( 90 - x ) 2
y = ( 90- 45 )/2
y = 22.5 meters
A(max) = 45*22.5 m²
A(max) = 1012.5 m²
If we get the second derivative of A(x) . A"(x) = - 1 A"(x) < 0
Then A(x) has a maximum for x = 45
Answer:
True
Step-by-step explanation:
-8 is less than or equal to -1
Answer:
ghjlgk
Step-by-step explanation:
