Question

Determine the perimeter of a rectangle with a length of 2 feet and a width of 6 inches.

Answer 1

Answer:

Your answer is 16 feet.

Step-by-step explanation:

P=2(l+w)=2·(2+6)=16

Answer 2

Option C

ANSWER:

The perimeter of the given rectangle is 5 feet

SOLUTION:

Given, a rectangle has length of 2 feet and width of 6 inches.

Let the length of rectangle be "l" = 2 feet

Width of the rectangle be "b" = 6 inches

Here, both the dimensions are not in same units, so we need to convert them into same units.

According to the options, let us convert them into feet. Length is already in feet but width is in inches so convert inches into feet  

We know that, 1 feet = 12 inches  

Hence 1 inch = $\frac{1}{12}$ feet

width (b) = 6 inches  

width = $6 \times \frac{1}{12}$ = 0.5 feet

Now, length (l) = 2 ft and width (b) = 0.5 ft

So, perimeter of the rectangle = 2(l + b)

= 2(2 + 0.5)

= $2 \times 2.5 = 5 feet$

Hence, the perimeter of the given rectangle is 5 feet