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Natalka [10]
3 years ago
9

How to solve a system of three equations with substitution

Mathematics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

Usually there are the variables x y z but it doesn't matter what they are.

Step-by-step explanation:

First choose your first variable to solve. Find x by putting all the numbers and variables to one side.

once you found x substitute the answer for x in all the equations. Next find y and substitute your answer in all the equations again.

Once you have solved 2 variables then you are able to solve z.  

If you have questions please feel free to ask in the comments below.

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PLZ HELP ASAP
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3 years ago
1.A five - layer of cake weighs half a kilogram per layer.In each layer,the cake is decorated with icing which weighs 15g.3 cand
julia-pushkina [17]

Answer:  2.815 kilograms

======================================================

Work Shown:

1 layer = 0.5 kg

5 layers = 5*(0.5 kg) = 2.5 kg

icing = 15 g = 15/1000 = 0.015 kg

1 candle = 100 g = 100/1000 = 0.1 kg

3 candles = 3*(0.1 kg) = 0.3 kg

------------------------

The five layers combine to 2.5 kg. On top of that we have 0.015 kg of icing, and then finally the three candles add 0.3 kg more weight.

The total weight is therefore: 2.5+0.015+0.3 = 2.815 kilograms

3 0
3 years ago
100 POINTS
ivann1987 [24]

Step-by-step explanation:

1. k = 76°

2. r = 25cm

3. as the drawing attached

one pair of parallel lines : AB and DC

one pair of equal angles : <em>L</em><em> </em>A and <em>L</em><em> </em>D

4. (7²× 3`¹)⁴×7^5 / (3² × 7^(-6))³

= (7^8 × 3`⁴)×7^5/ (3² × 7^(-6))³

= (7^13 × 3`⁴)/ (3^6 × 7^(-18))

= (7^(31) × 3^(-10))

= 7^31 / 3^10

3 0
3 years ago
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