1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
blondinia [14]
3 years ago
13

Will give brainliest answer

Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

a

Step-by-step explanation:

plz gimme brainliest

You might be interested in
in the lunch room there were 100 chocolate milk cartons at lunch when lunch was over 88 had been purchased
ratelena [41]

Answer:

12 left over 100-88=12

7 0
2 years ago
Find the requested unknown side of the following triangle
Salsk061 [2.6K]
*Answer* :
5.75
Explanation:
Let the unknown side = X
Cos() = adj/hyp
Cos(44)= X/8
X= 5.75
3 0
3 years ago
Given below are the graphs of two lines, y=-0.5 + 5 and y=-1.25x + 8 and several regions and points are shown. Note that C is th
zalisa [80]
We have the following equations:

(1) \ y=-0.5x+5 \\ (2) \ y=-1.25x+8

So we are asked to write a system of equations or inequalities for each region and each point.

Part a)

Region Example A

y \leq -0.5x+5 \\ y \leq -1.25x+8

Region B.

Let's take a point that is in this region, that is:

P(0,6)

So let's find out the signs of each inequality by substituting this point in them:

y \ (?)-0.5x+5  \\ 6 \ (?) -0.5(0)+5 \\ 6 \ (?) \ 5 \\ 6\ \textgreater \ 5 \\  \\ y \ (?) \ -1.25x+8 \\ 6 \ (?) -1.25(0)+8 \\ 6 \ (?) \ 8 \\ 6\ \textless \ 8

So the inequalities are:

(1) \ y  \geq  -0.5x+5 \\  (2) \ y  \leq  -1.25x+8

Region C.

A point in this region is:

P(0,10)

So let's find out the signs of each inequality by substituting this point in them:

y \ (?)-0.5x+5 \\ 10 \ (?) -0.5(0)+5 \\ 10 \ (?) \ 5 \\ 10\ \textgreater \ 5 \\ \\ y \ (?) \ -1.25x+8 \\ 10 \ (?) -1.25(0)+8 \\ 10 \ (?) \ 8 \\ 10 \ \ \textgreater \  \ 8

So the inequalities are:

(1) \ y  \geq  -0.5x+5 \\ (2) \ y  \geq  -1.25x+8

Region D.

A point in this region is:

P(8,0)

So let's find out the signs of each inequality by substituting this point in them:

y \ (?)-0.5x+5 \\ 0 \ (?) -0.5(8)+5 \\ 0 \ (?) \ 1 \\ 0 \ \ \textless \  \ 1 \\ \\ y \ (?) \ -1.25x+8 \\ 0 \ (?) -1.25(8)+8 \\ 0 \ (?) \ -2 \\ 0 \ \ \textgreater \ \ -2

So the inequalities are:

(1) \ y  \leq  -0.5x+5 \\ (2) \ y  \geq  -1.25x+8

Point P:

This point is the intersection of the two lines. So let's solve the system of equations:

(1) \ y=-0.5x+5 \\ (2) \ y=-1.25x+8 \\ \\ Subtracting \ these \ equations: \\ 0=0.75x-3 \\ \\ Solving \ for \ x: \\ x=4 \\  \\ Solving \ for \ y: \\ y=-0.5(4)+5=3

Accordingly, the point is:

\boxed{p(4,3)}

Point q:

This point is the x-intercept of the line:

y=-0.5x+5

So let:

y=0

Then

x=\frac{5}{0.5}=10

Therefore, the point is:

\boxed{q(10,0)}

Part b) 

The coordinate of a point within a region must satisfy the corresponding system of inequalities. For each region we have taken a point to build up our inequalities. Now we will take other points and prove that these are the correct regions.

Region Example A

The origin is part of this region, therefore let's take the point:

O(0,0)

Substituting in the inequalities:

y \leq -0.5x+5 \\ 0 \leq -0.5(0)+5 \\ \boxed{0 \leq 5} \\ \\ y \leq -1.25x+8 \\ 0 \leq -1.25(0)+8 \\ \boxed{0 \leq 8}

It is true.

Region B.

Let's take a point that is in this region, that is:

P(0,7)

Substituting in the inequalities:

y \geq -0.5x+5 \\ 7 \geq -0.5(0)+5 \\ \boxed{7 \geq \ 5} \\ \\ y  \leq \ -1.25x+8 \\ 7 \ \leq -1.25(0)+8 \\ \boxed{7 \leq \ 8}

It is true

Region C.

Let's take a point that is in this region, that is:

P(0,11)

Substituting in the inequalities:

y \geq -0.5x+5 \\ 11 \geq -0.5(0)+5 \\ \boxed{11 \geq \ 5} \\ \\ y \geq \ -1.25x+8 \\ 11 \ \geq -1.25(0)+8 \\ \boxed{11 \geq \ 8}

It is true

Region D.

Let's take a point that is in this region, that is:

P(9,0)

Substituting in the inequalities:

y  \leq -0.5x+5 \\ 0 \leq -0.5(9)+5 \\ \boxed{0 \leq \ 0.5} \\ \\ y \geq \ -1.25x+8 \\ 0 \geq -1.25(9)+8 \\ \boxed{0 \geq \ -3.25}

It is true

7 0
3 years ago
I NEED ANSWERS FAST Laura bought 8 3/10 yd of ribbon. She used 1 ⅖ yd to tie a package and 2 ⅓ yd to make a bow. Joe later gave
sergejj [24]

Answer:

9 1/6 yd

Step-by-step explanation:

First, list the lengths of ribbon Laura had or acquired:

8 3/10 yd + 4 3/5 yd.  This is equivalent to 8 3/10 yd + 4 6/10 yd, or

12 9/10 yd.

Next, list the lengths of ribbon Laura used:

1 2/5 yd + 2 1/3 yd.  The LCD here is 15, so we have 1 6/15 yd + 2 5/15 yd.

Summing up, we get 3 11/15 yd.

Subtract this length from the original 12 9/10 yard with which Laura began:

12 9/10 yd     or    12 27/30 yd (LCD is 30)

- 3 11/15 yd      or   -3 22/30 yd

Subtracting the latter two quantities, we get 9 5/30 yd, or 9 1/6 yd

7 0
3 years ago
Number 22 is the question
STALIN [3.7K]

Answer:

a^ 17

Step-by-step explanation:

If the bases are the same,

We are multiplying, we can add the exponents

a^b* a^c = a^(b+c)

a^4 * a^3 * a^ 10

a^ (4+3+10)

a^17

6 0
3 years ago
Other questions:
  • What is the base 10 representation of the number 1046(with an 8 underneath it)
    10·2 answers
  • In circle O, what is the measure of angle MAJ
    7·2 answers
  • one of the cats in the neighborhood had six kittens all about the same size. If each of the new kittens weighed about5 1/2 ounce
    13·2 answers
  • A bacterium cell splits into 2 cells every hour. Write and evaluate an exponential expression to find how many cells there will
    7·1 answer
  • An American football team is on their own 35-yard line they lose 5 yards on each of the next three plays at what yard are they n
    11·2 answers
  • Find the value of n <br> 0×39=n
    5·1 answer
  • Determine whether the expression is a polynomial. If it is a polynomial state the degree of the polynomial
    10·1 answer
  • POSSIBLE POINTS: 2
    7·2 answers
  • Linear or non linear?​
    9·2 answers
  • Two numbers are in the ratio 7:9 if the sum of the number is 112 then the lrger number is?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!