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Juliette [100K]
4 years ago
5

Which factor do biologists calculate when they determine whether a population is in Hardy-Weinberg equilibrium?

Biology
2 answers:
ziro4ka [17]4 years ago
8 0
Genotype frequencies
IRISSAK [1]4 years ago
7 0

Answer: The correct answer is-

genotype frequencies.

Hardy-Weinberg equilibrium is a condition according to which frequency of gene variant in the population of sexually reproducing individuals remains constant over generations ( that is it does not change from one generation to another generation).

There is an equation for the Hardy Weinberg law, which helps in determining the genotypes ( such as frequency of homozygous dominant, heterozygous domiant, and homozygous recessive genotypes). The equation is-

p^{2}+2pq+q^{2} =1

Where p² represents the homozygous dominant, 2pq represents heterozygous domiant, and q² for homozygous recessive genotypes.

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Each body cell of a chimpanzee contains 48 chromosomes. After mitosis, how many chromosomes are present in each cell?
nekit [7.7K]

Answer:

During both mitosis and meiosis, DNA replicates first during S phase of interphase. Each copy (DNA molecule) is called chromatid. Before anaphase they remain together, joined by the centromere in the chromosome.

Part 1: How many chromatids and chromosomes are present at:

(a) anaphase of mitosis: During this phase sister chromatids split. We would have 48 chromosomes in each pole and 48 chromatides.

(b) anaphase I of meiosis: During this phase homologous chromosomes split, being a reductional division. In each pole we will have half the chromosomes we had after DNA replication. This is 24 chromosomes but 48 chromatides (remember they will split during anaphase II).

(c) anaphase II of meiosis: This is an equational division, we will have 24 chromosomes in each pole and 24 chromatides. Each chromatid is considered a chromosome.

(d) G1 prior to mitosis: During this phase DNA has not replicated yet and it is not condensed either. This formed is called chromatin. We will assign one chromatid for each chromosome. This is a somatic cell, so: 48 chromosomes and 48 chromatids.

(e) G2 prior to mitosis: After S phase, we have duplicated all chromosomes. We will assign two chromatids per chromosome: this is 96 chromatides and 48 chromosomes.

(f) G1 prior to meiosis: Before DNA duplication, 48 chromosomes, 48 chromatids.

(g) Prophase of meiosis I: After DNA replication, condensation of the chromatin takes place: 48 chromosomes, 96 chromatids.

Part 2: How many chromatids or chromosomes are present in:

(h) An oogonial cell prior to S phase: This is G1 phase, 48 chromosomes.

(i) A spermatide: This is the male haploid gametid, after meiosis: 24 chromosomes and 24 chromatids.

(j) A primary oocyte arrested prior to ovulation: They are arrested at prophase I of meiosis. This means their DNA is still duplicated and chromatides have not divided yet. 48 chromosomes and 96 chromatids.

(k) A secondary oocyte arrested prior to fertilization: They are halted at metaphase II of meiosis, meaning they have half the chromosomes (24) but chromatids are still together (48).

(l) A second polar body: They suffered the same process as the mature ovum but remained with little cytoplasm. They have 24 chromosomes and 24 chromatids.

(m) A chimpanzee sperm: They have completed both meiosis as well, they have 24 chromosomes and 24 chromatids.  

Explanation:

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Which three of these classes of animals practice internal fertilization?
babymother [125]
Hello there!

The correct answers are:

A. Mammals
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Hope This Helps You!
Good Luck :)

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