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lora16 [44]
3 years ago
11

2x^2+3xy+y^2+5x+2y-3=0

Mathematics
1 answer:
zaharov [31]3 years ago
7 0

You didn't really ask a question, but that's a pretty interesting conic.

This is the rare conic that factors on the left:

2 x^2 + 3 x y + y^2 + 5 x + 2 y - 3 = (x + y + 3) (2 x + y - 1) = 0

So this is really two lines,

x + y + 3 = 0 \textrm{ and } 2x + y - 1 = 0

For fun, let's calculate the meet of those two lines:

y = -x -3

2x + -x -3 - 1 = 0

x = 4

y = -4 -3 = -7

This conic is two lines which meet at (4,-7)


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